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我正在使用maven構建我的項目。我想創建包含一些依賴項的組裝jar,所以我編寫了我的自定義組件描述符。Maven,Jar不包含主項目jar
的pom.xml
<plugin>
<artifactId>maven-assembly-plugin</artifactId>
<configuration>
<archive>
<manifest>
<mainClass>com.guavus.exporter.Exporter</mainClass>
</manifest>
</archive>
<descriptors>
<descriptor>/Users/archit.thakur/Documents/Code_dev_cdn_mapreduce/exporter/src/main/assembly/configurator.xml</descriptor>
<!-- <descriptorRef>jar-with-dependencies</descriptorRef> -->
</descriptors>
<finalName>Exporter-${project.version}</finalName>
<appendAssemblyId>false</appendAssemblyId>
</configuration>
<executions>
<execution>
<id>make-assembly</id>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
</execution>
</executions>
</plugin>
<plugin>
<artifactId>maven-jar-plugin</artifactId>
<version>2.3.1</version>
<executions>
<execution>
<id>default-jar</id>
<phase>none</phase>
</execution>
</executions>
</plugin>
裝配描述:
<assembly xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2 http://maven.apache.org/xsd/assembly-1.1.2.xsd">
<id>dep</id>
<formats>
<format>jar</format>
</formats>
<dependencySets>
<dependencySet>
<outputDirectory>${project.artifactId}</outputDirectory>
<unpack>true</unpack>
<useProjectArtifact>true</useProjectArtifact>
<includes>
<include>log4j:log4j</include>
<include>org.slf4j:slf4j-api</include>
<include>ch.qos.logback:logback-access</include>
<include>ch.qos.logback:logback-classic</include>
<include>ch.qos.logback:logback-core</include>
</includes>
</dependencySet>
</dependencySets>
</assembly>
的問題是,現在它正在創建的jar只有具有相關罐子。而不是將我的代碼製作成jar,並將其包含在最終的jar中。
爲什麼你需要在程序集描述符中使用「includes」?默認情況下,「dependencySet」包含所有依賴的jar。 –
是的。但我不想包含所有的依賴關係。如果我不使用「」,我將不得不使用標籤「」來指定我在裝配jar中不需要的依賴項。 –
你還試圖把你的項目放在「包含」內嗎? –