新的|雙輸出使用Scanner類for循環嵌套if語句

Question

我是一個非常新的編碼，需要一些幫助，我真的被卡住，四處張望，但無法找到我究竟做錯了什麼，所以搜索是不可能的。我有一段可怕的時間來解釋並試圖描述什麼是錯誤的，所以我會盡我所能，盡力而爲。

所以我有一個實驗室，你問用戶一個整數，但 ，第一個整數讀取後，我必須問用戶（使用字符串或字符），如果他們想要輸入另一個整數。如果用戶輸入'N'，它將跳過並結束程序。如果用戶輸入'Y'，他們將輸入另一個整數，它將跟蹤整數是偶數還是奇數，依此類推，直到用戶輸入'N'並在結尾處顯示偶數總數或輸入奇數。我以一種獨特的方式嘗試了這一點，我認爲這很可能不是一種「很整齊」的方式。輸出通常結束如： 要輸入整數嗎？： 是 輸入整數： 7是奇數！ （Y/N）？： 您是否有另一個整數可以輸入（Y/N）？： 輸入整數： 6是Even！ 你有另一個整數輸入（Y/N）？： ñ 你有另一個整數輸入（Y/N）？： 奇數：1 連號：1 我打的時候老是說「做你也想......「我不知道該怎麼解釋，我真的希望我不要模糊地謝謝你。

String Y = " "; 

    int integer = 0; 
    int even = 0; 
    int odd = 0; 
    int x = 0; 
    int b = 0; 




    System.out.println("Would you like to enter an integer?: "); 
    yes = in.nextLine(); 

    if(yes.equals("yes") || yes.equals("yes")) 
    { 


         System.out.println("Enter an integer: "); 
         integer = in.nextInt(); 
         if((integer % 2)==0||(integer ==0)) 
         { 
          System.out.println(integer+ " is Even!"); 
             even++; 
         } 
         else if((integer %1)==0) 
         { 
          System.out.println(integer+ " is Odd!"); 
            odd++; 
         } 
         x = 10; 


     for(int i = 5; i <= x; i++) 
       { 

        Y = in.nextLine(); 
        System.out.println("Do you have another integer to enter (Y/N)?: "); 





          if(Y.equals("Y")) 
          { 
           b = 1; 
           if(b == 1) 
           { 
             x = 10; 
             b = 0; 

             System.out.println("Enter an integer: "); 
             integer = in.nextInt(); 

             if((integer % 2)==0||(integer ==0)) 
             { 
              System.out.println(integer+ " is Even!"); 
              even++; 
             } 
             else if((integer %1)==0) 
             { 
              System.out.println(integer+ " is Odd!"); 
              odd++; 
             } 
           } 

          } 
          else if(Y.equals("N")) 
          { 
           Y = "N"; 
           x = 0; 
          } 
       } 
      System.out.println("Odd numbers: "+odd); 
      System.out.println("Even numbers: "+even); 

    } 





} 

Answer 1

這裏是什麼，我想你一個簡單的例子正在尋找：

public static void main(String[] args) { 
     System.out.println("Would you like to enter an integer"); 
     Scanner s = new Scanner(System.in); 
     String ans; 
     int odd = 0, even = 0, num; 
     boolean b = true; 
     while (b) { 
      ans = s.next(); 
      if (ans.equalsIgnoreCase("yes")) { 
       System.out.println("Please enter an integer"); 
       num = s.nextInt(); 
       if (num % 2 == 0) { 
        even++; 
       } else if (num % 1 == 0) { 
        odd++; 
       } 
       System.out.println("Do you have another integer to enter"); 
      } else { 
       b = false; 
      } 
     } 
     System.out.println("Odd: " + odd + " Even: " + even); 
    } 

然而，你需要整理它以準確地匹配你需要的東西。

Answer 2

讓我們分解你的代碼，也許你可以看到這裏有什麼問題。如果你剛剛一行一行地閱讀你的代碼，你自己就會看到大部分代碼。看起來您需要了解循環，特別是針對此任務的while循環。 https://docs.oracle.com/javase/tutorial/java/nutsandbolts/while.html

其次，要計算等於奇數或偶數的整數數量，請使用計數器。在本網站或谷歌上搜索大量資源。

我所有的評論指出，與代碼中的一些明顯的缺陷：

String Y = " "; 

int integer = 0; 
int even = 0; 
int odd = 0; 
int x = 0; 
int b = 0; 

// no main method 

//Specify what the user input should be to continue or to exit 
//your program in the first question, not later on. They have no idea 
//what word you are expecting them to type. What if they entered 
//"sure" or "yep" or "nah" 

System.out.println("Would you like to enter an integer?: "); 

//This needs to be declared. 
yes =in.nextLine(); 

//At this point, you have no way to exit the program because you have not utilized any 
//sort of loop. A while loop would work great here. 

// this if statement makes no sense and is redundant 

    if(yes.equals("yes")||yes.equals("yes")) 

{ 
    System.out.println("Enter an integer: "); 
    integer = in.nextInt(); 

    if ((integer % 2) == 0 || (integer == 0)) { 
     System.out.println(integer + " is Even!"); 
     even++; 
    } else if ((integer % 1) == 0) { 
     System.out.println(integer + " is Odd!"); 
     odd++; 
    } 

    //Why is int x even here? What is its purpose? 
    x = 10; 

    //Again, what is this for loop for? 
    for (int i = 5; i <= x; i++) { 



     //This entire section doesn't need to be here. Use a loop. 
    /* 
     Y = in.nextLine(); 
     System.out.println("Do you have another integer to enter (Y/N)?: "); 


     if (Y.equals("Y")) { 
      b = 1; 
      if (b == 1) { 
       x = 10; 
       b = 0; 

       System.out.println("Enter an integer: "); 
       integer = in.nextInt(); 

       if ((integer % 2) == 0 || (integer == 0)) { 
        System.out.println(integer + " is Even!"); 
        even++; 
       } else if ((integer % 1) == 0) { 
        System.out.println(integer + " is Odd!"); 
        odd++; 
       } 
      } 

     } else if (Y.equals("N")) { 
      Y = "N"; 
      x = 0; 
     } 
    }*/ 
    System.out.println("Odd numbers: " + odd); 
    System.out.println("Even numbers: " + even); 

} 

}