java，gameboard創建一個不需要的新行

我真的需要幫助，我浪費了很多時間搞清楚。所以我試圖做一個遊戲，其中，遊戲板表示爲數組。當我到達現場的右側時，一切都可以完美運行，新的線路被創建。這樣的：java，gameboard創建一個不需要的新行

0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 X 0 0 
0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 
d 
0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 X 0 
0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 
d 
0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 X 0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 
d 
Invalid move

無效的舉動

import java.util.Scanner; 

public class SimpleGame { 
    static String [] board; 
    int posy = 0; 
    int EnemyY = 65; 
public static void main(String [] args){ 
    String showField = " X 0 0 0 0 0 0 0 0 0 0 \n 0 0 0 0 0 0 0 0 0 0 0\n 0 0 0 0 0 0 0  0 0 0 0\n 0 0 0 0 0 0 0 0 0 0 0\n 0 0 0 0 0 0 0 0 0 0 0\n 0 0 0 0 0 0 0 0 0 0 M "; 
    System.out.print(showField); 
    System.out.print(""); 
    System.out.print(""); 
    String field = "0 0 0 0 0 0 0 0 0 0 0\n 0 0 0 0 0 0 0 0 0 0 0\n 0 0 0 0 0 0 0 0 0 0 0\n 0 0 0 0 0 0 0 0 0 0 0\n 0 0 0 0 0 0 0 0 0 0 0\n 0 0 0 0 0 0 0 0 0 0 0 "; 
    SimpleGame sg = new SimpleGame(); 
    while(true){ 
     sg.gamePlay(field); 
    } 
} 
public void gamePlay(String field){ 
    field.trim(); 
    board = field.split(" "); 
    Scanner sc = new Scanner(System.in); 
    System.out.println(""); 
    int len = 11; 
    String move = sc.nextLine(); 

    if(move.equals("d")){ 
     if(posy == 10 || posy == 21 || posy == 32 || posy == 43 || posy == 54 || posy == 65){ 
      System.out.println("Invalid move"); 
      return; 
     }else{ 
      posy += 1;    
      board[posy] = "X"; 
     } 
    }else if(move.equals("s")){ 
     if(55 <= posy && posy <= 66){ 
      System.out.println("Invalid move"); 
      return; 
     }else{ 
      posy += len; 
      board[posy] = "X"; 
     }  
    }else if(move.equals("a")){ 
     if(posy == 0 || posy == 11 || posy == 22 || posy == 33 || posy == 44 || posy == 55){ 
      System.out.println("Invalid move"); 
      return; 
     }else{ 
      posy -= 1; 
      board[posy] = "X"; 
     }  
    }else if(move.equals("w")){ 
     if(posy < 12){ 
      System.out.println("Invalid move"); 
      return; 
     }else{ 
      posy -= len; 
      board[posy] = "X"; 
     } 
    } 
    /*if(EnemyY == posy + len + 1 || posy == EnemyY + len + 1 || EnemyY == posy + len || posy == EnemyY +1){ 
     System.out.println("Game Over"); 
     return; 
    }*/ 

    for (String board1 : board){ 
     System.out.print(board1); 
     System.out.print(" "); 
    } 
} 
    public void addEnemy(int start, int x, int y, int [] board){ 

    } 

}

來源

2014-07-12 m2rt

[調試器]（http://en.wikipedia.org/wiki/Debugger） – drewmoore

當您到達場的右側時，是否要將該x移到下一行？或者你想要什麼？ –

當它到達右側的最後0時，程序會告訴無效的移動，並且用戶必須移動到其他地方，無效的移動消息可以工作 – m2rt

您分裂空格您field字符串，因此「0 \ n」被視爲一個令牌。因此，當您替換您的字段中的最後一個元素時，您也需要替換新行。

來源

2014-07-12 09:47:38 Ashalynd

java，gameboard創建一個不需要的新行

回答

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