創建子XML文件？

Question

我有一個XML文件是這樣的：

<?xml version="1.0" encoding="UTF-8" standalone="yes" ?> 
<Item> 
<Field Name="Filename">x1</Field> 
<Field Name="Year">y1</Field> 
<Field Name="Name">z1</Field> 
</Item> 
<Item> 
<Field Name="Filename">xn</Field> 
<Field Name="Year">yn</Field> 
<Field Name="Name">zn</Field> 
</Item> 

對於每一個項目，使用PowerShell的，我想創建一個XML文件，只有與它有關的信息。我該怎麼做？

Answer 1

你可以抓住所有<Item>節點與SelectNodes()，然後從每一個選擇Filename場SelectSingleNode()：

$xml = [xml]@' 
<?xml version="1.0" encoding="UTF-8" standalone="yes" ?> 
<Items> 
<Item> 
<Field Name="Filename">x1</Field> 
<Field Name="Year">y1</Field> 
<Field Name="Name">z1</Field> 
</Item> 
<Item> 
<Field Name="Filename">xn</Field> 
<Field Name="Year">yn</Field> 
<Field Name="Name">zn</Field> 
</Item> 
</Items> 
'@ 

foreach($item in $xml.SelectNodes('//Item')) 
{ 
    $Filename = $item.SelectSingleNode('//Field[@Name = "Filename"]').InnerText 

    # create your new xml document here, import $Item and save to $Filename 
} 

Answer 2

你可以嘗試這樣的事：

$xml = [xml]@' 
<?xml version="1.0" encoding="UTF-8" standalone="yes" ?> 
<Items> 
<Item> 
<Field Name="Filename">x1</Field> 
<Field Name="Year">y1</Field> 
<Field Name="Name">z1</Field> 
</Item> 
<Item> 
<Field Name="Filename">xn</Field> 
<Field Name="Year">yn</Field> 
<Field Name="Name">zn</Field> 
</Item> 
</Items> 
'@ 

$xml.Items.Item | ForEach-Object { 
    $filename = $_.SelectSingleNode("Field[@Name='Filename']").innertext 
    $file = New-Object xml 
    $file.InsertBefore($file.CreateXmlDeclaration("1.0","UTF-8","yes"),$file.DocumentElement) | Out-Null 
    $file.AppendChild($file.ImportNode($_,$true)) | Out-Null 
    $file.Save("C:\users\frode\Desktop\$($filename).xml") 
}