'Newtonsoft.Json.Linq.JObject'不包含'status'的定義錯誤

Question

responseString = {"status":"success","data":{"text":"Say Hello to\n\nAfrica’sfil’SI\nAnonymous\n\nSocial Network\nFrom Great Ho\nMitt\/6.6om","progress":100}} 

dynamic jsonDe = JsonConvert.DeserializeObject(responseString); 
      Debug.WriteLine(jsonDe.data); 

我在做什麼錯？

Answer 1

最後，這爲我工作：

public class responseData 
{ 
    public string status { get; set; } 
    public dataClass data { get; set; } 

} 

public class dataClass 
{ 
public string text { get; set; } 
public string progress { get; set; } 
} 
string myjsonstring = responseString; 
      responseData jsonDe = JsonConvert.DeserializeObject<responseData>(myjsonstring); 
      Debug.WriteLine(jsonDe.data.progress); // Outputs 100 
      Debug.WriteLine(jsonDe.status); // Outputs success