我想知道,我一直在努力MySQL查詢和MySQL結果代碼將我變成這樣MySQL查詢和結果語句的功能
function setting($claim){
$query = "SELECT `cases`, `hg`, `surname`, `firstname`, `type`, `claim`, `charge`, `damage`, `payment`, `repair`, `returned`, `comments`, `cost` FROM `rep_log` WHERE claim='$claim'";
$result = mysql_query($query) or die(mysql_error());
}
我試圖用這個讓我一個PHP函數可以更容易地更改所選擇的內容,而無需有不同的變量和東西堆只是更改查詢......所以基本上我做的是
echo setting("warrenty");
但我發現了一個錯誤:
Warning: mysql_fetch_row() expects parameter 1 to be resource, string given in ...
所以我想知道是它甚至有可能把一個MySQL查詢和結果到一個函數或只是一些東西,也不會發生......
如果有可能的幫助將是巨大的。
完整代碼
<?
// connection with the database
$dbhost = "localhost";
$dbuser = "root";
$dbpass = "";
$dbname = "netbookdb";
$result="";
mysql_connect($dbhost,$dbuser,$dbpass);
mysql_select_db($dbname);
// require the PHPExcel file
require 'Classes/PHPExcel.php';
// simple query
function setting($claim){
$query = "SELECT `cases`, `hg`, `surname`, `firstname`, `type`, `claim`, `charge`, `damage`, `payment`, `repair`, `returned`, `comments`, `cost` FROM `rep_log` WHERE claim='$claim'";
$result = mysql_query($query) or die(mysql_error());
}
// Create a new PHPExcel object
$objPHPExcel = new PHPExcel();
$objPHPExcel->getActiveSheet()->setTitle('Insurance');
echo setting('Warrenty');
$rowNumber = 1;
while ($row = mysql_fetch_row($result)) {
$col = 'A';
foreach($row as $cell) {
$objPHPExcel->getActiveSheet()->setCellValue($col.$rowNumber,$cell);
$col++;
}
$rowNumber++;
}
// Save as an Excel BIFF (xls) file
$objWriter = PHPExcel_IOFactory::createWriter($objPHPExcel, 'Excel5');
header('Content-Type: application/vnd.ms-excel');
header('Content-Disposition: attachment;filename="myFile.xls"');
header('Cache-Control: max-age=0');
$objWriter->save('php://output');
exit();
echo 'a problem has occurred... no data retrieved from the database';
?>
您知道嗎[[warranty]](http://dictionary.reference.com/browse/warranty)拼寫錯誤? –
'我得到一個錯誤,基本上說,沒有查詢已經運行,沒有結果已經返回......'你能發佈**精確**錯誤信息,而不是用你自己的話寫嗎? –
此錯誤警告:mysql_fetch_row()期望參數1是資源,字符串在 – Matthew