Python中的字符串，Int差異化和循環

Question

如何完成我的程序，該程序重複讀取數字，直到用戶輸入 「完成」。輸入「完成」後，打印數字的總數，計數和平均值。如果用戶輸入除數字以外的任何內容，則使用try和except檢測他們的錯誤 並打印錯誤消息並跳到下一個數字。

count = 0 
total = 0 

while True: 
    x = raw_input('Enter number') 
    x=int(x) 
    total = total + x 
    count = count + 1 
    average = total/count 
    print total, count, average 

Answer 1

下面的代碼應該是你想要的。

count = 0 
total = 0 

while True: 
    x = raw_input('Enter number: ') 
    if(x.lower() == "done"): 
     break 
    else: 
     try: 
      x=int(x) 
      total = total + x 
      count = count + 1 
      average = total/count 
     except: 
      print("That is not an integer. Please try again.") 

print total, count, average 

或在Python 3

count = 0 
total = 0 

while True: 
    x = input('Enter number: ') 
    if(x.lower() == "done"): 
     break 
    else: 
     try: 
      x=int(x) 
      total = total + x 
      count = count + 1 
      average = total/count 
     except: 
      print("That is not an integer. Please try again.") 

print(total, count, average)