jQuery的多級菜單左邊

Question

jQuery(document).ready(function() { 
    jQuery('#content').hide(); 
    jQuery('#last').mouseover(function() {}); 
    jQuery('#content').on('mouseout', function() {}); 
}); 

這是我的代碼在此我有兩個div ... 我需要離開菜單輸出的多層次.......檢查此鏈接http://javascript-array.com/scripts/multi_level_drop_down_menu/?j這樣我需要顯示我是沒有多少了解的jQuery可以請你在這方面

幫助這是我的JSP代碼

<div class="nav-menu nav-menu-style-<%= bulletStyle %>" > 


     <c:choose> 
      <c:when test='<%= (headerType.equals("root-layout") && (rootLayout != null)) %>'> 

       <% 
       String layoutURL = PortalUtil.getLayoutURL(rootLayout, themeDisplay); 
       String target = PortalUtil.getLayoutTarget(rootLayout); 
       String layoutName = rootLayout.getName(themeDisplay.getLocale()); 
       %> 

       <h2> 
        <a href="<%= layoutURL %>" <%= target %>><%= layoutName %></a> 
       </h2> 
      </c:when> 
      <c:when test='<%= headerType.equals("portlet-title") %>'> 
       <h2><%= themeDisplay.getPortletDisplay().getTitle() %></h2> 
      </c:when> 
      <c:when test='<%= headerType.equals("breadcrumb") %>'> 
        <p id="last"> <liferay-ui:breadcrumb /></p> 
      </c:when> 
     </c:choose> 
<div id="content"> 
     <% 
     if (!hidden) { 
      StringBuilder sb = new StringBuilder(); 

      _buildNavigation(rootLayout, layout, selBranch, themeDisplay, 1, includedLayouts, nestedChildren, sb); 

      String content = sb.toString(); 

      /*if (!nestedChildren) { 
       content = StringUtil.replace(content, "</a><ul class", "</a></li></ul><ul class"); 
       content = StringUtil.replace(content, "</ul></li>", "</ul><ul class=\"layouts\">"); 
      }*/ 
     %> 

      <%= content %> 

     <% 
     } 
     %> 
    </div> 
    </div> 

感謝

Answer 1

1. Multilevel Dropdown Menu Issues with Jquery

2. http://jsfiddle.net/MkR7W/3/

希望這將要給你一個想法來解決這個PBLM。