我已經寫了其中連接三個表的客戶表,計算各個字段的值的查詢集合函數,並返回銷售和收入由銷售代表細分的概述:左聯接和使用次數,如果
SELECT
u.id AS `userId`,
u.`username`,
(SELECT COUNT(*) FROM `SaleSet` s WHERE s.`pitchedBy_id` = `userId` AND s.setCompleteAt BETWEEN '2012-07-02 00:00:00' AND '2012-07-02 23:59:59') AS `transfers`,
COUNT(c.id) AS `closes`,
COUNT(IF(c.saleType_id = 1, 1, NULL)) AS `regS_sales`,
COUNT(IF(c.saleType_id = 2, 1, NULL)) AS `pd_sales`,
COUNT(IF(c.saleType_id = 4, 1, NULL)) AS `attempted_sales`,
COUNT(IF(c.CustomerStatus_id IN (5,6,9,16), 1,NULL)) AS `complete`,
COUNT(IF(c.CustomerStatus_id IN (8,18), 1,NULL)) AS `canceled`,
COUNT(IF(c.CustomerStatus_id IN (1,12,13), 1,NULL)) AS `pending`,
COUNT(IF(c.CustomerStatus_id = 20, 1,NULL)) AS `post_dated`,
SUM(IF(p.saleType_id = 2, p.`authOnlyAmount`,0)) AS `pdPotRev`,
#SUM(IF(c.saleType_id = 2 AND t.`captured` = 0, p.`authOnlyAmount`,0)) AS `pdCapRev`,
SUM(t.amount) AS `fwRevAuthed`,
SUM(IF(p.saleType_id = 2 AND t.`captured` = 0, t.amount,0)) AS `fwCaptured`
FROM customer c
LEFT JOIN `User` u ON u.id = c.`salesRep_id`
LEFT JOIN `Transaction` t
ON t.`customer_id` = c.`id`
AND t.transactionType = 'Auth'
LEFT JOIN `Purchase` p ON p.`customer_id` = c.`id`
#WHERE c.`salesRep_id` = 10
WHERE c.`activationDate` BETWEEN '2012-07-02 00:00:00' AND '2012-07-02 23:59:59'
GROUP BY u.`id`
爲什麼此列返回0而不是t.amount之和:SUM(IF(p.saleType_id = 2 AND t.captured = 0, t.amount,0)) AS fwCaptured
?正如你所看到的,我做了上面兩行完全一樣的東西,它工作正常。
下面是結果的一個例子:
userId username transfers closes regS_sales pd_sales attempted_sales complete canceled pending post_dated pdPotRev fwRevAuthed fwCaptured
10 doughaase 17 4 3 1 0 4 0 0 0 50.00 298.00 0.00
65 davidgarber 13 5 5 0 0 4 0 0 0 0.00 595.00 0.00
70 morgantaylor 5 2 2 0 0 0 2 0 0 0.00 198.00 0.00
76 shayans 8 1 0 1 0 1 0 0 0 99.00 99.00 0.00
96 regananson 5 3 3 0 0 3 0 0 0 0.00 248.00 0.00
的pdPotRev使用在完全相同的方式完全相同的功能和完美。
此外,它沒有什麼區別如果我指定t.captured = 0或1。 – 2012-07-20 21:49:46