獲取節點的內部XML作爲字符串在Java中的DOM

Question

我有一個XML org.w3c.dom.Node中，看起來像這樣：

<variable name="variableName"> 
    <br /><strong>foo</strong> bar 
</variable> 

如何獲得<br /><strong>foo</strong> bar部分作爲字符串？

Answer 1

org.w3c.dom.Node沒有簡單的方法。 getTextContent（）將每個子節點的文本連接在一起。 getNodeValue（）將爲您提供當前節點的文本，如果它是Attribute，CDATA或Text節點。因此，您需要使用getChildNodes（），getNodeName（）和getNodeValue（）的組合來序列化節點以構建字符串。

您也可以使用存在的各種XML序列化庫之一來執行此操作。有XStream甚至JAXB。這在XML serialization in Java?

Answer 2

中討論相同的問題。爲了解決這個問題，我寫這個輔助功能：

public String innerXml(Node node) { 
    DOMImplementationLS lsImpl = (DOMImplementationLS)node.getOwnerDocument().getImplementation().getFeature("LS", "3.0"); 
    LSSerializer lsSerializer = lsImpl.createLSSerializer(); 
    NodeList childNodes = node.getChildNodes(); 
    StringBuilder sb = new StringBuilder(); 
    for (int i = 0; i < childNodes.getLength(); i++) { 
     sb.append(lsSerializer.writeToString(childNodes.item(i))); 
    } 
    return sb.toString(); 
} 

Answer 3

，如果你不希望訴諸外部庫，以下解決方案可能會派上用場。如果你有一個節點「」你要提取的父元素的兒童遊樂步驟如下：

StringBuilder resultBuilder = new StringBuilder(); 
    // Get all children of the given parent node 
    NodeList children = parent.getChildNodes(); 
    try { 

     // Set up the output transformer 
     TransformerFactory transfac = TransformerFactory.newInstance(); 
     Transformer trans = transfac.newTransformer(); 
     trans.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes"); 
     trans.setOutputProperty(OutputKeys.INDENT, "yes"); 
     StringWriter stringWriter = new StringWriter(); 
     StreamResult streamResult = new StreamResult(stringWriter); 

     for (int index = 0; index < children.getLength(); index++) { 
      Node child = children.item(index); 

      // Print the DOM node 
      DOMSource source = new DOMSource(child); 
      trans.transform(source, streamResult); 
      // Append child to end result 
      resultBuilder.append(stringWriter.toString()); 
     } 
    } catch (TransformerException e) { 
     //Errro handling goes here 
    } 
    return resultBuilder.toString(); 

Answer 4

如果您使用jOOX，你可以用你的節點在jquery樣的語法，只是通話toString()它：

$(node).toString(); 

它使用的身份變壓器內部，就像這樣：

ByteArrayOutputStream out = new ByteArrayOutputStream(); 
Transformer transformer = TransformerFactory.newInstance().newTransformer(); 
transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes"); 
Source source = new DOMSource(element); 
Result target = new StreamResult(out); 
transformer.transform(source, target); 
return out.toString(); 

Answer 5

大廈的盧卡斯埃德爾的解決方案上面，我們可以在.NET提取innerXml等作爲下面

public static String innerXml(Node node,String tag){ 
     String xmlstring = toString(node); 
     xmlstring = xmlstring.replaceFirst("<[/]?"+tag+">",""); 
     return xmlstring;  

}

public static String toString(Node node){  
    String xmlString = ""; 
    Transformer transformer; 
    try { 
     transformer = TransformerFactory.newInstance().newTransformer(); 
     transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes"); 
     //transformer.setOutputProperty(OutputKeys.INDENT, "yes"); 
     StreamResult result = new StreamResult(new StringWriter()); 

     xmlString = nodeToStream(node, transformer, result); 

    } catch (TransformerConfigurationException e) { 
     // TODO Auto-generated catch block 
     e.printStackTrace(); 
    } catch (TransformerFactoryConfigurationError e) { 
     // TODO Auto-generated catch block 
     e.printStackTrace(); 
    } catch (TransformerException e) { 
     // TODO Auto-generated catch block 
     e.printStackTrace(); 
    }catch (Exception ex){ 
     ex.printStackTrace(); 
    } 

    return xmlString;    
} 

例：

If Node name points to xml with string representation "<Name><em>Chris</em>tian<em>Bale</em></Name>" 
String innerXml = innerXml(name,"Name"); //returns "<em>Chris</em>tian<em>Bale</em>" 

Answer 6

我與最後應答該方法 'nodeToStream（）' 是未定義的問題;因此，我的版本在這裏：

public static String toString(Node node){ 
    String xmlString = ""; 
    try { 
     Transformer transformer = TransformerFactory.newInstance().newTransformer(); 
     transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes"); 
     //transformer.setOutputProperty(OutputKeys.INDENT, "yes"); 

     Source source = new DOMSource(node); 

     StringWriter sw = new StringWriter(); 
     StreamResult result = new StreamResult(sw); 

     transformer.transform(source, result); 
     xmlString = sw.toString(); 

    } catch (Exception ex) { 
     ex.printStackTrace(); 
    } 

    return xmlString; 
} 

Answer 7

擴展Andrey M的答案，我不得不略微修改代碼以獲取完整的DOM文檔。如果你只是使用

NodeList childNodes = node.getChildNodes(); 

它沒有包含我的根元素。以包括的根元素（和獲得完整的.xml文件）我使用：

public String innerXml(Node node) { 
    DOMImplementationLS lsImpl = (DOMImplementationLS)node.getOwnerDocument().getImplementation().getFeature("LS", "3.0"); 
    LSSerializer lsSerializer = lsImpl.createLSSerializer(); 
    lsSerializer.getDomConfig().setParameter("xml-declaration", false); 
    StringBuilder sb = new StringBuilder(); 
    sb.append(lsSerializer.writeToString(node)); 
    return sb.toString(); 
} 

Answer 8

下面是一個替代的解決方案，以提取org.w3c.dom.Node中的內容。 此解決方案也該節點的內容不包含XML標籤：

private static String innerXml(Node node) throws TransformerFactoryConfigurationError, TransformerException { 
    StringWriter writer = new StringWriter(); 
    String xml = null; 
    Transformer transformer = TransformerFactory.newInstance().newTransformer(); 
    transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes"); 
    transformer.transform(new DOMSource(node), new StreamResult(writer)); 
    // now remove the outer tag.... 
    xml = writer.toString(); 
    xml = xml.substring(xml.indexOf(">") + 1, xml.lastIndexOf("</")); 
    return xml; 
}