JavaScript拆分字符串變量（不使用任何額外變量）

我正在使用MVC模型（django）。我在模板中有一個for循環，用於從sqlite3數據庫收集數據。我需要填充一個JavaScript變量（使用JSON格式），它將數據庫中的radar.client字段分開。該字段是逗號分隔值字符串。我需要解析它到不同的「兒童」價值的json。現在讓我進入練習。JavaScript拆分字符串變量（不使用任何額外變量）

產生的JSON變種的代碼如下所示：

var json = { 
    "id": "1", 
    "name": "Server", 
    "children": [ 
     {% if clave_radar % } 
     {% for radar in clave_radar % } 
     {"id": "{{ radar.key }}", 
     "name": "{{ radar.ap }}", 
     "data": {"": "", "": ""}, 
     "children": [ 
//This is where I need to split in different children 
       {"id": "1_{{ radar.key }}", 
       "name": "{{ radar.clients }}", 
       "data": {"": "", "": ""}, 
       "children": []}, 

     ]}, 
      {% endfor % } 
     {% endif % } 
    ], 
};

現在讓我告訴你的服務器處理的碼看起來像客戶端的例子：

var json_test={ 
    "id": "1", 
    "name": "Server", 
    "children": [ 
     { 
     "id": "13", 
     "name": "WLT", 
     "data": {"": "","": ""}, 
     "children": [ 
      { 
      "id": "1_13", 
      "name": "081196(Intel Corporate), 68a3c4(Liteon Technology Corporation), b8d9ce(Samsung Electronics)", 
      "data": {"": "","": ""}, 
      "children": [] 
      }, 
      //Children Liteon and Samsung should appear here and not packed in 1_13 
     ] 
     }, 
     ], 
    };

而且這是我努力使它看起來像這樣：

varjson_real={ 
    "id": "1", 
    "name": "Server", 
    "children": [ 
    { 
     "id": "13", 
     "name": "WLT", 
     "data": {"": "","": ""}, 
     "children": [ 
     { 
      "id": "1_13", 
      "name": "081196(Intel Corporate)", 
      "data": {"": "","": ""}, 
      "children": [] 
     }, 
     { 
      "id": "2_13", 
      "name": "68a3c4(Liteon Technology Corporation)", 
      "data": { 
      "": "", 
      "": "" 
      }, 
      "children": [] 
     }, 
     { 
      "id": "3_13", 
      "name": "b8d9ce(Samsung Electronics)", 
      "data": {"": "","": ""}, 
      "children": [] 
     }, 
     ] 
    }, 
    ] 
};

來源

2014-02-23 EnriqueH

什麼是你的問題其實？試圖結束這個... –

我剛剛找到了解決這個問題的方法。首先我被this how to split a string to an array with django

啓發我添加此功能可將radar型號：

def list_clients(self): 
    return self.clientes_encontrados.split('), ')

然後，代碼想是這樣的：

var json_radar = { 
    "id": "1", 
    "name": "Server", 
    "children": [ 
    {% if clave_radar %} 
     {% for radar in clave_radar %} 
     {"id": "{{ radar.key }}", 
     "name": "{{ radar.ap }}", 
     "data": {"": "","": ""}, 
     "children": [ 
      {% if radar.clients != "null" %} 
      {% for client in radar.list_clients %} 
      {"id": "1_{{ radar.key }}", 
      "name": "{{ client }}", 
      "data": {"": "", "": ""}, 
      "children": []}, 
      {% endfor %} 
      {% endif %} 

     ]}, 
     {% endfor %} 
    {% endif %} 
    ], 
};

來源

2014-02-23 19:16:44 EnriqueH

爲什麼你不循環c如下所示：

var json = { 
"id": "1", 
"name": "Server", 
"children": [ 
{% if clave_radar % } 
    {% for radar in clave_radar % } 
     {"id": "{{ radar.key }}", 
     "name": "{{ radar.ap }}", 
     "data": {"": "", "": ""}, 
     "children": [ 
     {% for client in radar.clients %} 
       {"id": "1_{{ radar.key }}", 
       "name": "{{ client }}", 
       "data": {"": "", "": ""}, 
       "children": []}, 
     {% endfor % } 
     ]}, 
    {% endfor % } 
{% endif % } 
], 
};

來源

2014-02-23 16:15:49

我已經試過這種方式，它將在「081196（Intel Corporate），68a3c4（Liteon Technology Corporation）的每個字符上遍歷一個新的循環（您創建的'for'循環）， b8d9ce（三星電子）「，我需要在這種特殊情況下（逗號分隔）發生3次。 – EnriqueH

我不知道它是一個字符串，反正你可以for循環改成這樣： {％的客戶在radar.clients.split（「」）％}這是爲什麼你會這個字符串分割到3個對象。 –

您正在幫助我接近解決方案......我無法在django中使用'.split'。不過，我現在正在閱讀如何從模型中拆分http://stackoverflow.com/questions/8317537/django-templates-split-string-to-array – EnriqueH

JavaScript拆分字符串變量（不使用任何額外變量）

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