如何Tkinter的執行Python 3的程序一個鍵

Question

我試圖從Tkinter的執行蟒蛇3文件，當我點擊一個按鈕

Tkinter的代碼

import tkinter as tk 
import subprocess as sub 

WINDOW_SIZE = "600x400" 

root = tk.Tk() 
root.geometry(WINDOW_SIZE) 

tk.Button(root, text="Create Motion!", command=lambda: sub.call('home/pi/motion1.py')).pack() 

但收到錯誤時我運行程序

Exception in Tkinter callback 
Traceback (most recent call last): 
    File "/usr/lib/python3.5/tkinter/__init__.py", line 1562, in __call__ 
    return self.func(*args) 
    File "/home/pi/AnimationGUI.py", line 11, in <lambda> 
    tk.Button(root, text="Create Motion!", command=lambda: sub.call('motion1.py')).pack() 
    File "/usr/lib/python3.5/subprocess.py", line 247, in call 
    with Popen(*popenargs, **kwargs) as p: 
    File "/usr/lib/python3.5/subprocess.py", line 676, in __init__ 
    restore_signals, start_new_session) 
    File "/usr/lib/python3.5/subprocess.py", line 1282, in _execute_child 
    raise child_exception_type(errno_num, err_msg) 
FileNotFoundError: [Errno 2] No such file or directory: 'motion1.py' 

Answer 1

你這樣做是錯的。做到這一點的正確方法是讓「motion1.py」中的某個函數做一些事情。假設你稱這個函數爲「main」（很常見）。那麼你的代碼是：

import tkinter as tk 
import motion1 

WINDOW_SIZE = "600x400" 

root = tk.Tk() 
root.geometry(WINDOW_SIZE) 

btn = tk.Button(root, text="Create Motion!", command=motion1.main) 
btn.pack() 

假設你的代碼和「motion1.py」在同一個文件夾中。