註冊php文件。

我一直在試圖讓這個註冊PHP的工作。我猜，我很近。但是有一個問題。結果總是一個重定向到主頁的按鈕（當你閱讀代碼時，你會知道我在說什麼）。如果你能找到問題，請告訴我。註冊php文件。

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en" id="jmtoday" class=" no_js"> 
<head> 
<link href='icon.jpg' rel='icon' type='image/jpg'/> 
<meta http-equiv="Content-type" content="text/html; charset=utf-8" /> 
<meta http-equiv="Content-language" content="en" /> 
<LINK REL=StyleSheet HREF="Mainstyles.css" TYPE="text/css"></link> 
<Title>Sign up to JM Today</title> 
</head> 
<body> 
<?php 
$dbservertype='mysql'; 
$servername='localhost'; 
$dbusername='***'; 
$dbpassword='***'; 
$dbname='jmtdy'; 
function connecttodb($servername,$dbname,$dbuser,$dbpassword) 
{ 
    global $link; 
    $link=mysql_connect("$servername","$dbuser","$dbpassword"); 
    if(!$link){ 
    die("Could not connect to MySQL"); 
    } 
    mysql_select_db("$dbname",$link) or die ("could not open db".mysql_error()); 
} 
connecttodb($servername,$dbname,$dbusername,$dbpassword); 
?> 


<?php 

$username=mysql_real_escape_string($_POST['username']); 
$password=mysql_real_escape_string($_POST['password']); 
$password2=mysql_real_escape_string($_POST['password_confirmation']); 
$todo=mysql_real_escape_string($_POST['todo']); 
$email=mysql_real_escape_string($_POST['email']); 
$fname=mysql_real_escape_string($_POST['fname']); 
$lname=mysql_real_escape_string($_POST['lname']); 



if(isset($todo) and $todo=="post"){ 

$status = "OK"; 
$msg=""; 
} 

if(!isset($username) OR strlen($username) <3){ 
$msg=$msg."Username should be equal to or more than 3 characters long<BR/>"; 
$status= "NOTOK"; 
}  

if(mysql_num_rows(mysql_query("SELECT username FROM users WHERE username = '$username'")or die (mysql_error()))){ 
$msg=$msg."Username already exists. Please try another one<BR/>"; 
$status= "NOTOK";}  


if (strlen($password) < 3){ 
$msg=$msg."Password must be more than 3 charactors long<BR/>"; 
$status= "NOTOK"; 
}  

if ($password <> $password2){ 
$msg=$msg."Passwords are not identical.<BR/>"; 
$status= "NOTOK"; 
}  


if($status="NOTOK"){ 
echo "$msg<br/><input type='button' value='Retry' onClick='history.go(-1)'>"; 
} 
else { 
if(mysql_query("insert into users(username,password,email,fname,lname) values('$username','$password','$email','$fname','$lname')")or die (mysql_error())){ 
echo "Welcome, You have successfully signed up"; 
} 
else { 
echo "Database Problem, please contact Site admin"; 
} 

} 
?> 
</body> 
</html>

來源

2010-12-19 Samir Ghobril

你錯過了=上線

if($status="NOTOK"){

它將分配「NOTOK」到$地位，成爲邏輯真。

來源

2010-12-19 20:49:05 Andy

謝謝，這解決了問題！ – 2010-12-20 15:53:23

沒問題，如果是正確的答案，你能接受嗎？ – Andy 2010-12-20 16:12:14

註冊php文件。

回答

相關問題