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我有一個基於續集的類，我需要做一些總結。如何使用續集寶石獲得group_and_count的結果？
我正在做group_and_count，我可以看到它正在生成正確的查詢。然而，當我嘗試訪問的結果，續集試圖要挾行到類，我訪問過：
[33] pry(main)> grouped = Pancakes::Stack.active.group_and_count('health_state')
=> #<Sequel::Mysql2::Dataset: "SELECT 'health_state', count(*) AS `count` FROM `pancakes_stacks` WHERE (`deleted_at` IS NULL) GROUP BY 'health_state'">
[34] pry(main)> grouped.each_entry { |row| puts row }
I sequel: (0.001344s) SELECT 'health_state', count(*) AS `count` FROM `pancakes_stacks` WHERE (`deleted_at` IS NULL) GROUP BY 'health_state'
#<Pancakes::Stack:0x000000089251a0>
=> #<Sequel::Mysql2::Dataset: "SELECT 'health_state', count(*) AS `count` FROM `pancakes_stacks` WHERE (`deleted_at` IS NULL) GROUP BY 'health_state'">
[35] pry(main)> grouped.first
I sequel: (0.001502s) SELECT 'health_state', count(*) AS `count` FROM `pancakes_stacks` WHERE (`deleted_at` IS NULL) GROUP BY 'health_state' LIMIT 1
I sequel: (0.001243s) SELECT * FROM `pancakes_stacks` WHERE (`id` IS NULL) LIMIT 1
=> #<Pancakes::Stack:0x44b068c>
我能得到什麼，我需要通過周圍的ORM的東西的工作，但似乎需要我重新實現active上述方法，並找出如何從類名獲得表名：
[38] pry(main)> groupie = grouped.db[:pancakes_stacks].where(deleted_at:nil).group_and_count(:health_state)
=> #<Sequel::Mysql2::Dataset: "SELECT `health_state`, count(*) AS `count` FROM `pancakes_stacks` WHERE (`deleted_at` IS NULL) GROUP BY `health_state`">
[39] pry(main)> groupie.each_entry { |row| puts row }
I sequel: (0.001598s) SELECT `health_state`, count(*) AS `count` FROM `pancakes_stacks` WHERE (`deleted_at` IS NULL) GROUP BY `health_state`
{:health_state=>nil, :count=>3}
{:health_state=>"healthy", :count=>10}
是不是有一個更簡單的方法？我在querying page上花了很多時間，但沒有一個例子顯示如何訪問結果。