2014-09-29 79 views
0

我試圖從我的objective-c應用程序向我的服務器發送HTTP發佈請求。我嘗試了很多不同的東西,但我無法獲得請求主體上的內容請求。使用url上的參數它工作得很好,但我需要發送保留字符的字符串。帶有正文內容的HTTP發佈請求失敗

這是我的課負責請求:

#import "CLPUtilRequest.h" 
static NSString *baseURL = @"http://localhost:8080/cl-mobile"; 

@implementation CLPUtilRequest 

//Parameteres on the URL (working!!) 
+ (NSData *) makeHttpRequest:(NSString *)url { 
//Set info for webservice 
NSString *urlString = baseURL; 
urlString = [urlString stringByAppendingString:url]; 
NSURL *resquestUrl = [NSURL URLWithString:urlString]; 
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:resquestUrl]; 

[request setHTTPMethod: @"POST"]; 
[request setValue:@"application/http" forHTTPHeaderField:@"Accept"]; 
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; 

//Call the webservice 
NSError *errorReturned = nil; 
NSHTTPURLResponse *theResponse =[[NSHTTPURLResponse alloc]init]; 
return [NSURLConnection sendSynchronousRequest:request returningResponse:&theResponse error:&errorReturned]; 
} 

//Parameteres on the bodt (not working!!) 
+ (NSData *) makeHttpRequestContentOnBody:(NSString *)url withContent:(NSString *)content { 
NSData *postData = [content dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES]; 
NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]]; 
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init]; 

[request setURL:[NSURL URLWithString:url]]; 
[request setHTTPMethod:@"POST"]; 
[request setValue:postLength forHTTPHeaderField:@"Content-Length"]; 
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; 
[request setHTTPBody:postData]; 

NSError *errorReturned = nil; 
NSHTTPURLResponse *theResponse =[[NSHTTPURLResponse alloc]init]; 
NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&theResponse error:&errorReturned]; 
return data; 
} 

@end 

而這正是我所說的請求。

NSString *contentString = @"chaveUsuarioEmpresa="; 
contentString = [contentString stringByAppendingString:appDelegate.clinica.chave]; 
contentString = [contentString stringByAppendingString:@"&chaveAgendamento="]; 
contentString = [contentString stringByAppendingString:appDelegate.agendamento.chave]; 
contentString = [contentString stringByAppendingString:@"&anamnese="]; 
contentString = [contentString stringByAppendingString:self.texto.text]; 
NSData *dataResponse = [CLPUtilRequest makeHttpRequestContentOnBody:@"/agendamento/anamnese/save" withContent:contentString]; 

調用請求後,我errorReturned給我下面的(調試):NSURLError *域名:@ 「NSURLErrorDomain」 - 代碼:-1002

我試圖做的是在這裏的鏈接中(但沒有做到):Sending an HTTP POST request on iOS

在此先感謝!

回答

0

根據Apple's Error Codes -1002是一個不受支持的url的代碼。實際上你是把它發送到/agendamento/anamnese/save,像你一樣,你在其他呼叫做

+ (NSData *) makeHttpRequest:(NSString *)url { 
    //Set info for webservice 
    NSString *urlString = baseURL; 
    urlString = [urlString stringByAppendingString:url]; 
    NSURL *resquestUrl = [NSURL URLWithString:urlString]; 

而在makeHttpRequestContentOnBody:withContent:使用不變的URL字符串傳遞/agendamento/anamnese/save

嘗試

不預置基本URL
+ (NSData *) makeHttpRequestContentOnBody:(NSString *)url withContent:(NSString *)content 
{ 
    NSData *postData = [content dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES]; 
    NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]]; 
    NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init]; 

    NSString *urlString = baseURL; 
    urlString = [urlString stringByAppendingString:url]; 

    [request setURL:[NSURL URLWithString:urlString]]; 
    [request setHTTPMethod:@"POST"]; 
    [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; 
    [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; 
    [request setHTTPBody:postData]; 

    NSError *errorReturned = nil; 
    NSHTTPURLResponse *theResponse =[[NSHTTPURLResponse alloc]init]; 
    NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&theResponse error:&errorReturned]; 
    return data; 
} 
+0

非常感謝,真的是我的一個愚蠢的錯誤:( 現在它的工作很好! – phellipeperin 2014-09-29 19:25:47