Question

這是我在我的房間

<?php 
    include'db.php'; 
    $sql=mysql_query("Select*from tb_rooms1"); 
    echo "<div class='container'>"; 
    echo "<div class='scrolltable'>"; 
    echo "<table class= 'table table-striped table-bordered'>"; 
    echo"<th><div align='center'>ID</div></th>"; 
    echo"<th><div align='center'>Image</div></th>"; 
    echo"<th><div align='center'>Room Name</div></th>"; 
    echo"<th><div align='center'>Description</div></th>"; 
    echo"<th><div align='center'>Price Per Night</div></th>"; 
    echo"<th><div align='center'>Status</div></th>"; 
    echo"<th><div align='center'>Reserve</div></th>"; 

    while($row=mysql_fetch_array($sql)) 
    { 
     @$id=$row['eid']; 

     echo"<tr align='center'>"; 
     echo"<td><div style='font-size:11px;' align='center'>".$row['roomID']</div></td>"; 
     echo"<td><div style='font-size:11px;' align='center'><img width=72 height=52 alt='Unable to View' src=".$row['image']."></div></td>"; 
     echo"<td><div style='font-size:11px;' align='center'>".$row['name']."</div></td>"; 
     echo"<td><div style='font-size:11px;' align='center'>".$row['description']."</div></td>"; 
     echo"<td><div style='font-size:11px;' align='center'>".$row['price']."</div></td>"; 
     echo"<td><div style='font-size:11px;' align='center'>".$row['status']."</div></td>"; 
     echo"<td><div align='center' style='margin-top:30px'><input style='margin-top:-2px;' type='checkbox'></div></td>"; 
    } 
    echo"</table>"; 
    echo"</div>"; 
    echo"</div>"; 
?> 

我不知道我怎麼可以顯示我已經選擇了另一頁房間的信息表的代碼。有人能幫我嗎？我

Answer 1

讓您的房間可點擊，並通過傳遞房間ID作爲參數

echo"<td><div style='font-size:11px;' align='center'><a href='otherpage.php?roomid={$row['roomID']}'> Room {$row['roomID']}</a></div></td>"; 

在你的其他PHP文件你會有這樣的事情：

otherpage.php 
<?php 
include'db.php'; 
$roomid = $_GET['roomid']; 
$lookupQuery = mysqli_query("SELECT * FROM tb_rooms1 WHERE roomID = [$roomid]"); 

...顯示但你想要的數據

你需要考慮的一件事情是mysql注入，因爲你的代碼是使用mysql並且參數被直接傳遞到你的查詢中...