2013-03-05 35 views
0

你好,我有一個驗證碼使用Ajax的工作,但它沒有將我的表格的相關信息進入數據庫,它插入空行,我沒有任何線索,爲什麼 這裏是我的代碼:阿賈克斯驗證碼後,將其插入數據庫

require_once('inc/recaptchalib.php'); 
$publickey = "6LdW1N0SAAAAADMIPPkOGd939meXV9a9qDwwcxbu"; // you got this from the signup page 
$privatekey = ""; 


<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.0/jquery.min.js"  type="text/javascript"></script> 
<script type="text/javascript"> 
var RecaptchaOptions = { 
    theme : 'clean' 
}; 
</script> 
<script type="text/javascript"> 
function validateCaptcha() 
{ 
    challengeField = $("input#recaptcha_challenge_field").val(); 
    responseField = $("input#recaptcha_response_field").val(); 
    //alert(challengeField); 
    //alert(responseField); 
    //return false; 
    var html = $.ajax({ 
    type: "POST", 
    url: "ajax.recaptcha.php", 
    data: "recaptcha_challenge_field=" + challengeField + "&recaptcha_response_field=" + responseField, 
    async: false 
    }).responseText; 

    if(html == "success") 
    { 
     $("#captchaStatus").html("Success. Submitting form."); 
     return false; 
     // Uncomment the following line in your application 
     //return true; 
    } 
    else 
    { 
     $("#captchaStatus").html("Your captcha is incorrect. Please try again"); 
     Recaptcha.reload(); 
     return false; 
    } 
} 
</script> 

這裏是我想要插入到數據庫中的表單:

<form id="loginform" name="loginform" action="" method="post" enctype="multipart/form-data" onSubmit="return validateCaptcha()" > 
         <fieldset class="step"> 

          <p> 
           <label for="nick">Nickname:</label> 
           <input type="text" name="nick" value="" id="nicknamee" value="" > 
          </p> 
          <p> 
           <label for="email">Email:</label> 
           <input type="text" name="email" value="" id="email_comm" value="" > 
          </p> 

          <p> 
           <textarea class="text-input textarea wysiwyg" name="add_comment" id="text_commentt"></textarea> 
          </p>';?> 
          <div id="login"> 

    <?php echo recaptcha_get_html($publickey);?> 

<p style="color: red;" id="captchaStatus">&nbsp;</p> 

</div> 

<?php 
    echo'       
          <p style="margin-top:200px;"><button id="vote_petiton_submit" type="submit" ></button> 
          </p> 

         </fieldset> 
         </form> 

的ReCaptcha現在的核查和數據庫插入文件。驗證是可以的,只需要在數據庫中插入數據不正確,它不會發布值。

<?php 
require_once('inc/recaptchalib.php'); 
require_once('engine/db.php'); 
$publickey = "6LdW1N0SAAAAADMIPPkOGd939meXV9a9qDwwcxbu"; // you got this from the signup page 
$privatekey = ""; 
mysql_query("SET NAMES utf8"); 
$resp = recaptcha_check_answer ($privatekey, 
           $_SERVER["REMOTE_ADDR"], 
           $_POST["recaptcha_challenge_field"], 
           $_POST["recaptcha_response_field"]); 

if ($resp->is_valid) { 
    ?>success<? 
    $nick=$_REQUEST['nick']; 
     $type=0; 
      $email=$_REQUEST['email']; 
      $descr=$_REQUEST['add_comment']; 
      $descriere=strip_tags($descr,'<br><p><a><i><u><b>');  
      $id=150; 

      $insert = "INSERT INTO comments (`nickname`,`desc`,`email`,`type`,`id_pet_dem_des`) 
         VALUES ('$nick','$descriere','$email','$type',$id)"; 
       $result = mysql_query($insert) 
        or die("query failed: " . mysql_error()); 


      $queryz = "update petition set comments=comments+1 where id_petition='$id'"; 
    $resultz = mysql_query($queryz) 
     or die("query failed: " . mysql_error()); 
} 
else 
{ 
    die ("The reCAPTCHA wasn't entered correctly. Go back and try it again." . 
     "(reCAPTCHA said: " . $resp->error . ")"); 
} 
?> 

Thnx提前。

+1

我已刪除了您的私鑰(需要同行評審),從阿賈克斯後量變到質變的數據修復它,但它仍然在編輯歷史可見。如果您刪除問題並重新發布而沒有私鑰,這可能是最好的選擇。 – 2013-03-05 18:54:03

+0

沒有人可以照亮我?:) – 2013-03-05 21:40:17

+0

這可能是最好的你重新生成你的私鑰 – Mchl 2013-03-05 22:03:57

回答

1

我與

data: $('#loginform').serialize() + "recaptcha_challenge_field=" + challengeField + "&recaptcha_response_field=" + responseField,