上還內置了陣列

Question

我不知道值執行的foreach如果我正確的措辭這個問題，但基本上我從WordPress的下面陣列結果我試圖處理：

Array 
(
    [0] => WP_User Object 
     (
      [data] => stdClass Object 
       (
        [ID] => 3 
        [user_login] => Jean Gomes 
        [user_pass] => $P$BvW6LK9/blGKLuSj.9spNPW3.v104.. 
        [user_nicename] => jean-gomes 
        [user_email] => jean.gomes@dpa.dev 
        [user_url] => 
        [user_registered] => 2014-08-28 10:56:39 
        [user_activation_key] => 
        [user_status] => 0 
        [display_name] => Jean Gomes 
       ) 

      [ID] => 3 
      [caps] => Array 
       (
        [author] => 1 
       ) 

      [cap_key] => dpa2335327_capabilities 
      [roles] => Array 
       (
        [0] => author 
       ) 

      [allcaps] => Array 
       (
        [upload_files] => 1 
        [edit_posts] => 1 
        [edit_published_posts] => 1 
        [publish_posts] => 1 
        [read] => 1 
        [level_2] => 1 
        [level_1] => 1 
        [level_0] => 1 
        [delete_posts] => 1 
        [delete_published_posts] => 1 
        [wpseo_bulk_edit] => 1 
        [author] => 1 
       ) 

      [filter] => 
     ) 

    [1] => WP_User Object 
     (
      [data] => stdClass Object 
       (
        [ID] => 4 
        [user_login] => Tammy Day 
        [user_pass] => $P$BejydpFxKDp60WruV71u0/JnJm9o.E. 
        [user_nicename] => tammy-day 
        [user_email] => tammy.day@dpa.dev 
        [user_url] => 
        [user_registered] => 2014-08-28 10:57:23 
        [user_activation_key] => 
        [user_status] => 0 
        [display_name] => Tammy Day 
       ) 

      [ID] => 4 
      [caps] => Array 
       (
        [author] => 1 
       ) 

等

我想對這個ID使用這些結果執行foreach。

E.g.

foreach ($authors as $author_id) { 

但我不知道如何訪問ID。我想：

foreach ($authors->ID as $author_id) { 

但很明顯這可不行，因爲有之前的數，是否有一個等價的：

foreach ($authors['X']->ID as $author_id) { 

，我可以用？

對不起，我知道這可能是一個愚蠢的問題，但我很困難。我知道我可能不得不在foreach中做一個foreach，但是我根本無法弄清楚語法。

Answer 1

foreach (array_expression as $value) 

在每次迭代中，當前元素的值被分配給$ value並且內部數組指針前進一個（所以在下一次迭代中，您將查看下一個元素）。

閱讀有關foreach環詳情this文檔頁面：

在你的情況$值將指針的WP_User Object實例。要訪問該用戶的ID剛讀對象的屬性ID

foreach ($authors as $author) { 
    $author_id = $author->ID; 
} 

Answer 2

你不能代替試試這個的foreach：

$i=0; 
while ($i<count($authors)){ 
$author_id = $authors[$i]['data']['id']; 
//Do whatever you want here. 
$i=$i+1; 
} 

Answer 3

由於傾倒狀態，數組元素是WP_User的實例。可以使用下面的循環來獲取的ID：

foreach ($authors as $User) { 
    $author_id = $User->ID; 
    // Act 
} 

對於WP_User類的參考，請參閱http://codex.wordpress.org/Class_Reference/WP_User