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我試圖用該Java腳本提交我的表單。但它沒有按原樣運行，它沒有從腳本中獲得價值。它只適用於我的HTML體內的警報編碼，但它沒有讀取函數check（），我的表單是否有一些問題？我的提交按鈕不起作用
<form name="myForm" method="post" onsubmit="return check()">
<table width="100%">
<tr>
<div id="space">
YOUR DETAILS
</div><!-- space -->
</tr>
<tr>
<td width="186"><span style="color:red;">*</span>First Name</td>
<td width="720">
<input type="text" name="fname">
</td>
</tr>
<tr>
<td width="186"><span style="color:red;">*</span>Last Name</td>
<td width="720">
<input type="text" name="lname">
</td>
</tr>
<tr>
<td width="186"><span style="color:red;">*</span>Email</td>
<td width="720">
<input type="email" name="email">
</td>
</tr>
<tr>
<td width="186"><span style="color:red;">*</span>Telephone</td>
<td width="720">
<input type="tel" name="telephone">
</td>
</tr>
<tr>
<td width="186">Fax</td>
<td width="720">
<input type="tel" name="fax">
</td>
</tr>
<tr>
<td width="186">Company</td>
<td width="720">
<input type="text" name="company">
</td>
</tr>
<tr>
<td width="186">Company ID</td>
<td width="720">
<input type="text" name="cid">
</td>
</tr>
<tr>
<td width="186"><span style="color:red;">*</span>Address 1</td>
<td width="720">
<input type="text" name="add1">
</td>
</tr>
<tr>
<td width="186">Address 2</td>
<td width="720">
<input type="text" name="add2">
</td>
</tr>
<tr>
<td width="186"><span style="color:red;">*</span>City</td>
<td width="720">
<input type="text" name="city" >
</td>
</tr>
<tr>
<td width="186">Poscode</td>
<td width="720">
<input type="text" name="poscode" >
</td>
</tr>
<tr>
<td width="186"><span style="color:red;">*</span>Country</td>
<td width="720">
<select name="country">
<option value="malaysia">Malaysia</option>
<option value="australia">Australia</option>
<option value="japan">Japan</option>
<option value="newzealand">New Zealand</option>
</select>
</td>
</tr>
</table>
<br><br>
<input type="button" onclick="check()" name="submit" value="Submit" class="sbutton" />
<button name="subcancel" class="sbutton" value="Cancel" >CANCEL</button>
</form>
這是我的javascript功能
function check(){
alert('hi');
var isi1=document.forms["myForm"]["fname"].value;
var isi2=document.forms["myForm"]["lname"].value;
var isi3=document.forms["myForm"]["email"].value;
var isi4=document.forms["myForm"]["tel"].value;
var isi5=document.forms["myForm"]["add1"].value;
var isi6=document.forms["myForm"]["city"].value;
var isi7=document.forms["myForm"]["country"].value;
if (isi1 == "") {
alert("Please complete all your detail with '*' symbol!");
return false;
}
else if(isi2 ==""){
alert("Please complete your detail!");
return false;
}
else if(isi3 ==""){
alert("Please complete your detail!");
return false;
}
else if(isi4 ==""){
alert("Please complete your detail!");
return false;
}
else if(isi5 ==""){
alert("Please complete your detail!");
return false;
}
else if(isi6 ==""){
alert("Please complete your detail!");
return false;
}
else{
alert("Hi "+isi1+" "+isi2+"!! You are succesfully registered to our bookstore!!");
return true;
}
}
Javascri pt！= Java –
好吧，您不要取消點擊 – epascarello
從標記中刪除'onsubmit =「return check（）」'。將check（）事件處理程序添加到按鈕按下。使用AJAX手動提交或添加表單POST目標和'form.submit（）'您可能無法從check（）處理程序返回以停止發生提交。所以用像if（isValid）form.submit（）'ps這樣的邏輯來重新使用它：你可以遍歷所有這些值來檢查它們是不是空字符串。 –
Shilly