2016-01-29 16 views
-2

對不起,如果我問得太多,這只是我耗盡時間,我真的需要你的幫助,我試圖根據用戶輸入INSERT數據到我的表中.. 這是我的表..和相關如何將數據添加到您的連接表

這是錯誤

You have an error in your SQL syntax; check the manual that corresponds 
to your MySQL server version for the right syntax to use near 
'WHERE Jobs.CatagoryId= 1' at line 2 

.....

Jobs 
---- 
JobID 
CategoryID 
JobName 
JobDescription 
JobNumber 

Categories 
--------- 
CategoryID // 11 categories.. 
CategoryDescription 

基於來自droplist用戶的選舉,它會選擇分類數據。應貯存在 和插入所有數據用戶在框中領域

 <?php 
    session_start(); 
    if(isset($_SESSION['username'])){ 
     if(isset($_POST['add'])){ 

    if(isset($_POST['add'])) 
    { 
     $errorMessage = ""; 

    if(($_POST['lists'])== 0) // trying to get error if user don't choose. 
     { 
     $errorMessage .= "<li>You Forgot to Choose !</li>";  
     } 
    if(empty($_POST['JobName'])) 
    { 
    $errorMessage .= "<li>You Forgot To Enter A Job Name !</li>"; 
    } 
    if(empty($_POST['Description'])) 
    { 
    $errorMessage .= "<li>You Forgot To Enter A Description !</li>"; 
    } 
    if(empty($_POST['NoStudent'])) 
    { 
    $errorMessage .= "<li>You Forgot To Enter A Student Number !</li>"; 
    } 
    if(empty($_POST['dueDate'])) 
    { 
     $errorMessage .= "<li>You Forgot To Enter A Due Date !</li>"; 
       } 
            $lists = $_POST['lists']; 
            $JN = $_POST['JobName']; 
            $DES = $_POST['Description']; 
            $NoS = $_POST['NoStudent']; 
            $DuDate = $_POST['dueDate']; 

            if(!empty($errorMessage)) 
            { 
            echo("<p>There was an error with your form:</p>\n"); 
            echo("<ul>" . $errorMessage . "</ul>\n"); 
            die(); 
            } 
           } 

           $table="";  
           switch($lists) 
           { 
            case '1': 
             $table ="1"; 
            break; 
            case '2': 
             $table ="2"; 
            break; 
           //.........other cases..........// 
            case '3': 
             $table ="3"; 
            break; 
            case '4': 
             $table ="4"; 
            break; 
            case '5': 
             $table ="5"; 
            break; 
            case '6': 
             $table ="6"; 
            break; 
            case '7': 
             $table ="7"; 
            break; 
            case '7': 
             $table ="8"; 
            break; 
            case '8': 
             $table ="9"; 
            break; 
            case '9': 
             $table ="10"; 
            break; 
            case '10': 
             $table ="11"; 
            break; 
            case '11': 
             $table ="12"; 
            break; 

            default; 
             echo 'Unsupported category'; 
            break; 
           } 
           if ($table != ""){ 

           //Connect to DB 
         include('../CIEcon.php'); //$dbCIE 


           $sql = "INSERT INTO Jobs(JobName,Description,NoStudent,DueDate) 
         VALUES ('$JN','$DES','$NoS','$DuDate') WHERE Jobs.CatagoryId= ". $table . " "; 



           mysqli_query($dbCIE, $sql) or die(mysqli_error($dbCIE)); 

           } 


           echo "You Successfuly Added a new Job ..."; 

           mysqli_close($dbCIE); 


       } 

       else { echo ' 
       <form action= "AddJob.php" method = "post"> 
       <table width ="100%" cellpadding ="4" border="1" > 

       <tr style ="color: white; background-color: #f26822 ; "> 
       <th>Select a Catagory</th> 
       <th>Jobs Name</th> 
       <th>Description</th> 
       <th> No Students needed</th> 
       <th>Due Date</th> 
       </tr>'; 



        echo "<tr> 


       <td>". 

       "<select name = lists > 
        <option name= nothing value= 0 selected >Choose a Catagory</option> 
        <option name= nothing value= 1> Advertising  </option> 
        <option name= nothing value= 2> Fiscal   </option> 
        <option name= nothing value= 3> Food   </option> 
        <option name= nothing value= 4> Shopping  </option> 
        <option name= nothing value= 5> Rentals   </option> 
        <option name= nothing value= 6> Setting up  </option> 
        <option name= nothing value= 7> Performances </option> 
        <option name= nothing value= 8> Registration/Ushering </option> 
        <option name= nothing value= 9> Master of Ceremonies </option> 
        <option name= nothing value= 10> Cleaning up </option> 
        <option name= nothing value= 11> Others  </option> 

       </select>" 



        ." </td> 
       <td> "."<input type=text name=JobName maxlength=50 placeholder='Enter Job Name '>" ." </td> 
       <td> "."<input type=text name=Description maxlength=50 placeholder='Enter Description '>" ." </td> 
       <td> ". "<input type=text name=NoStudent maxlength=50 onkeypress=return isNumber(event) placeholder='ONLY NUMBERS'/>" . "</td> 
       <td>". "<input type=text name=dueDate maxlength=50 placeholder='YYYY-MM-DD'>" ." </td> 
       </tr>"; 




       echo ' 
       </table> 
       <br/> 

       <div align="center"> 
       <input type="submit" name="add" value="Add" /> 
       <input type="reset" value="Clear" /> 




       </div> 

       </form> 

       '; 
       } 



    }else{echo "must logout to see this page..!!";} 

    ?> 

    <html> 


    <style type="text/css"> 

    body{ 

    margin-top: 80px; 
    background-color: #23438e ; 
    } 
    table{ 
     background-color: white; 
    } 




    </style> 



    <head><title> Add.. </title></head> 
    <br> 
    <body> 
    <a href= "../AdminIndex.php" > <button style="margin-left:auto;margin-right:auto;display:block;margin-top:0%;margin-bottom:0%"> Main Page </button></a> 

    </body> 
    </html> 
+1

那麼,它有什麼問題? –

+0

它告訴我在MYSQL查詢中有一個錯誤 – aymanko

+0

沒有'''INSERT INTO ... WHERE ...''' - 請參閱語法參考,例如, http://dev.mysql.com/doc/refman/5.7/en/insert.html –

回答

1

進入,如果$表中存在到「Categories.CategotyID」和「Jobs.JobID」是自動遞增,查詢可以是這樣:

$sql = "INSERT INTO Jobs(`JobID`, `CategoryID`, `JobName`,`Description`,`NoStudent`) 
VALUES (NULL,{$table},'$JN','$DES','$NoS'); 

$sql = "INSERT INTO Jobs VALUES (NULL,{$table},'$JN','$DES','$NoS'); 

您的查詢包含屬性DuDate,存在到喬布斯?

+0

我明白了。它工作正常,謝謝你這麼多先生。 – aymanko

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