文本框內未定義的變量

Question

正如您所看到的，我在我的texboxes中出現錯誤。任何人都可以幫助我解決這個錯誤？文本框裏面

的錯誤有以下幾種：

** 

> aic: 

** 
<br /><b>Notice</b>: Undefined variable: aic in <b>C:\xampp\htdocs\test\index.php</b> on line <b>34</b><br /> 
<br /><b>Notice</b>: Undefined variable: aic in <b>C:\xampp\htdocs\test\index.php</b> on line <b>35</b><br /> 
<br /><b>Notice</b>: Undefined variable: aic in <b>C:\xampp\htdocs\test\index.php</b> on line <b>36</b><br /> 
<br /><b>Notice</b>: Undefined variable: aic in <b>C:\xampp\htdocs\test\index.php</b> on line <b>37</b><br /> 

** 

> Name List: 

** 
<br /><b>Notice</b>: Undefined variable: name in <b>C:\xampp\htdocs\test\index.php</b> on line <b>41</b><br /> 
<br /><b>Notice</b>: Undefined variable: name in <b>C:\xampp\htdocs\test\index.php</b> on line <b>42</b><br /> 
<br /><b>Notice</b>: Undefined variable: name in <b>C:\xampp\htdocs\test\index.php</b> on line <b>43</b><br /> 
<br /><b>Notice</b>: Undefined variable: name in <b>C:\xampp\htdocs\test\index.php</b> on line <b>44</b><br /> 

> **Address:** 

<br /><b>Notice</b>: Undefined variable: address in <b>C:\xampp\htdocs\test\index.php</b> on line <b>48</b><br /> 
<br /><b>Notice</b>: Undefined variable: address in <b>C:\xampp\htdocs\test\index.php</b> on line <b>49</b><br /> 
<br /><b>Notice</b>: Undefined variable: address in <b>C:\xampp\htdocs\test\index.php</b> on line <b>50</b><br /> 
<br /><b>Notice</b>: Undefined variable: address in <b>C:\xampp\htdocs\test\index.php</b> on line <b>51</b><br /> 

PHP代碼：

<?php 
if(isset($_POST['code'])){ 
include('include/connect.php'); 

$batchcode = $_POST['code']; 
$sql = mysql_query("SELECT aic,batchcode,address,name FROM tb_app WHERE batchcode LIKE '$batchcode'"); 
while($rows = mysql_fetch_array($sql)){ 
    $aic[] = $rows['aic']; 
    $name[] = $rows['name']; 
    $address[] = $rows['address']; 
} 
} 
?> 

的html代碼：

Search Batchcode:<input type="text" name="code" id="query" /><br /> 
<form> 
<table> 
<tr> 
<td> 
aic: <br /> 
<input type="text" name="optA1" value="<?php echo $aic[0] ?>" /> <br /> 
<input type="text" name="optA2" value="<?php echo $aic[1] ?>" /> <br /> 
<input type="text" name="optA3" value="<?php echo $aic[2] ?>" /> <br /> 
<input type="text" name="optA4" value="<?php echo $aic[3] ?>" /> <br /> 
</td> 
<td> 
Name List: <br /> 
<input type="text" name="optB1" value="<?php echo $name[0] ?>" /> <br /> 
<input type="text" name="optB2" value="<?php echo $name[1] ?>" /> <br /> 
<input type="text" name="optB3" value="<?php echo $name[2] ?>" /> <br /> 
<input type="text" name="optB4" value="<?php echo $name[3] ?>" /> <br /> 
</td> 
<td> 
Address: <br /> 
<input type="text" name="optC1" value="<?php echo $address[0] ?>" /> <br /> 
<input type="text" name="optC2" value="<?php echo $address[1] ?>" /> <br /> 
<input type="text" name="optC3" value="<?php echo $address[2] ?>" /> <br /> 
<input type="text" name="optC4" value="<?php echo $address[3] ?>" /> <br /> 
</td> 
</form> 

我不希望我的文本框進行循環，因爲每個他們有獨特的名字，不適合未來使用我的JavaScript。

Answer 1

通常這個錯誤，當您嘗試反響，沒有定義，在這種情況下出現變量，這意味着你的代碼不while循環，和進入這意味着你的查詢結果爲空 。

嘗試：

if($sql) { 
    while($rows = mysql_fetch_array($sql)){ 
     $aic[] = $rows['aic']; 
     $name[] = $rows['name']; 
     $address[] = $rows['address']; 
    } 
}else { 
    $aic  = array('empty','empty','empty','empty'); 
    $name = array('empty','empty','empty','empty'); 
    $address = array('empty','empty','empty','empty'); 
} 

順便說一句，我想你想這個查詢和之前或$batchcode後失蹤的%，你可以試試這個太：

$sql = mysql_query("SELECT aic,batchcode,address,name FROM tb_app 
WHERE batchcode LIKE '%".$batchcode."%'"); 

或本：

$sql = mysql_query("SELECT aic,batchcode,address,name FROM tb_app 
    WHERE batchcode = '".$batchcode."'"); 

Answer 2

我看到你正在查找基於批處理代碼的表，所以如果你ar e尋找確切的批次代碼使用=

$sql = mysql_query("SELECT aic,batchcode,address,name FROM tb_app WHERE batchcode = '".$batchcode."'");