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我試圖通過Hibernate來連接到Oracle,我得到一個異常Hibernate的異常,同時通過休眠
org.hibernate.HibernateException:
No Hibernate Session bound to thread, and configuration does not allow creation of non-transactional one here
at org.springframework.orm.hibernate3.SpringSessionContext.currentSession(SpringSessionContext.java:63)
at org.hibernate.impl.SessionFactoryImpl.getCurrentSession(SessionFactoryImpl.java:574)
at com.mycompany.infra.daoimpl.GenericDAOImpl.findAll(GenericDAOImpl.java:133)
at com.mycompany.testHibernate.TeamTest.main(TeamTest.java:29)
我定義的,看起來像這樣的應用程序上下文連接到Oracle: applicationContext.xml中
<?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd">
<!-- There is no use for this bean at current moment. --> <bean id="OnMediaSessionFactory" parent="sessionFactory"> <property name="schemaUpdate" value="${hibernate.schema_update}" /> <property name="hibernateProperties"> <props>
<!-- prop key="hbm2ddl.auto">${hibernate.hbm2ddl.auto}</prop
-->
<prop key="show_sql">${hibernate.show_sql}</prop>
<prop key="connection.provider_class">${hibernate.connection.provider_class}</prop>
<prop key="hibernate.dialect">${hibernate.dialect}</prop>
<prop key="hibernate.max_fetch_depth">${hibernate.max_fetch_size}</prop>
<prop key="hibernate.default_batch_fetch_size">${hibernate.default_batch_fetch_size}</prop>
<prop key="hibernate.jdbc.fetch_size">${hibernate.jdbc.fetch_size}</prop>
<prop key="hibernate.jdbc.batch_size">${hibernate.jdbc.batch_size}</prop>
<prop key="hibernate.cache.use_query_cache">${hibernate.cache.use_query_cache}</prop>
<prop key="hibernate.cache.provider_class">${hibernate.cache.provider_class}</prop>
<prop key="hibernate.cache.use_second_level_cache">${hibernate.cache.use_second_level_cache}</prop> </props> </property> </bean>
<import resource="classpath:/applicationContext-hibernate.xml" />
<bean id="messageHandlerSpring" class="com.mycompany.messagehandler.MessageHandlerSpringImpl"> </bean>
<bean id="omTeamDAO" class="com.mycompany.infra.daoimpl.MutableDAOImpl"> <constructor-arg value="com.mycompany.model.OmTeam" />
我的測試連接看起來是這樣的:
ApplicationContext ctx = new ClassPathXmlApplicationContext(
"applicationContext.xml"); SessionFactory sessions = (SessionFactory) ctx
.getBean("OnMediaSessionFactory");
GenericDAO<OmTeam> dao = new MutableDAOImpl<OmTeam>(OmTeam.class,sessions, 10);
try { Collection<OmTeam> teams = dao.findAll(); for (OmTeam team : teams) {
System.out.println(team.getOmTeamName()); } } catch (Exception e) { System.out.println("Exception while loading teams"); e.printStackTrace();
}
在另一個項目中的以下行工作:
集合團隊= dao.findAll();
我的代碼有什麼問題?
我很想得到一個非常快速有效的答案.. 謝謝!
Rivki。
如果您花時間格式化粘貼的代碼,則您的問題更有可能得到解答。目前,由於幾行很長的行和不好的縮進,讀起來非常困難。 – Codo 2011-01-23 11:21:17