Play Framework 2.2.1 - 添加非播放Java項目作爲子項目

Question

我試圖添加一個非播放Java項目作爲子項目。主項目是Play Java應用程序，子項目與主項目位於同一目錄中。我遵循給予here的指示。我build.sbt看起來像

import play.Project._ 

name := "main-project" 

version := "1.0" 

libraryDependencies ++= Seq(javaJdbc, javaEbean) 

playJavaSettings 

lazy val mainProject = project.in(file(".")) 
    .aggregate(subProject) 
    .depends(subProject) 

lazy val subProject = project.in(file("../sub-projects/sub-project-1")) 

這裏是我的目錄結構

D: 
|-- projects 
| |-- main-project 
| |-- sub-projects 
| | | |-- sub-project-1 
| | | |-- sub-project-2 

當我嘗試編譯主體工程，我得到以下錯誤。

[info] Loading project definition from D:\projects\main-project\project 
D:\projects\main-project\build.sbt:13: error: value depends is not a member of sbt.Project 
possible cause: maybe a semicolon is missing before `value depends'? 
.depends(subProject) 
^ 
[error] sbt.compiler.EvalException: Type error in expression 
[error] Use 'last' for the full log. 

Answer 1

它應該是dependsOn而不是depends。

你也應該指向從文件夾根兩個項目：

name := "java-test" 

version := "1.0-SNAPSHOT" 

playJavaSettings 

lazy val mainProject = project.in(file(".")) 
    .aggregate(subProject, playProject) 
    .dependsOn(subProject, playProject) 


lazy val subProject = project.in(file("sub-projects/sub-project-1")) 

//play project depends on subProject... 
lazy val playProject = project.in(file("play-project")).dependsOn(subProject)