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Question

ab<- as.factor(c("A","B","A","C","B","C","C")) 
a123<- as.factor(c(NA,NA,NA,465,NA,532,456)) 
dd<- as.data.frame(cbind(ab,a123)) 

替換的NA，這是該我有，我想替換NA與0值。如果柱AB的值是A否則NA我曾嘗試下面的代碼數據幀= 1

：

dd$Amount[is.Na(dd$Amount)]<- ifelse(my_dd$Activity=="Beneficiary Added", 0,1) 

我收到以下錯誤：

> dd$Amount[is.Na(dd$Amount)]<- ifelse(my_dd$Activity=="Beneficiary Added", 0, 1) 
Error in `*tmp*`$Amount : object of type 'closure' is not subsettable 

Answer 1

一個答案加上data.table（在我看來更清晰的語法）的例子我的評論：

library(data.table) 

df <- data.frame(abc = c("A","B","A","C","B","C","C"), a123 = c(NA,NA,NA,465,NA,532,456)) 
dt <- data.table(df) 

# "Classic" data.frame syntax 
df$a123[is.na(df$a123)] <- ifelse(df[is.na(df$a123), 'abc'] == "A", 0, 1) 
# data.table one 
dt[is.na(a123), a123 := ifelse(abc == "A", 0, 1)] 

Answer 2

這裏是我的建議。

abc<- c("A","B","A","C","B","C","C") 
df<- data.frame(cbind(abc,a123),stringsAsFactors =FALSE) 
df$your_var=ifelse(df$abc %in% "A" & df$a123 %in% NA, 0, ifelse(df$a123 %in% NA,1,df$a123) 
print(df) 

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帕夫洛