我如何拼接一個標量變量？

Question

$ab = "asljdhashdklasjkl ;dajs;ld"; 

我想要$ab的前10個字符。

可以使用splice函數嗎？

Answer 1

substr($ab, 0, 10) 

瞭解更多關於substr功能here

Answer 2

#! /usr/bin/perl 
use strict; 
my $info = "asljdhashdklasjkl ;dajs;ld"; 
my @personal = split(//, $info); 
print @personal[0..9]; 


C:\Documents and Settings\Administrator>perl perltest.pl 
asljdhashd 
C:\Documents and Settings\Administrator> 
C:\Documents and Settings\Administrator>type perltest.pl 
#! /usr/bin/perl 
use strict; 
my $info = "asljdhashdklasjkl ;dajs;ld"; 
my @personal = split(//, $info); 
print @personal[0..9]; 
C:\Documents and Settings\Administrator> 

Answer 3

SUBSTR您例如偉大工程。接頭的陣列上運行，所以你需要往返它：

#!/usr/bin/perl 
my ($ab, @ab, @first_ten, $first_ten); 

$ab = "asljdhashdklasjkl ;dajs;ld"; 

@ab = split(//, $ab); 
@first_ten = splice(@ab, 0, 10); 

$first_ten = join('', @first_ten);