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建模我需要創建經由AJAX填充數據與下面的代碼的表:值傳遞給從控制器
VIEW:
<form class="form-inline" id="form_filter" method="POST">
<label for="date_from">From </label>
<input type="date" name="date_from">
<label for="date_to"> To </label>
<input type="date" name="date_to">
<input type="button" name="btn_view_records" value="Filter Date" class="btn btn-success btn-sm" id="btn_view_records">
</form>
$('#btn_view_records').click(function(){
$.ajax({
type:"POST",
data:$('#form_filter').serialize(),
datataype:"JSON",
url:"<?php echo site_url('pakyaw/get_filtered_data');?>",
success:function(data){
$("#log-list").html(data);
}
});
});
CONTROLLER:
public function get_filtered_data(){
$this->load->library('table');
$this->table->set_heading('Bio Id', 'Log Date', 'Time In', 'Time Out', 'Time Rendendered');
$style = array('table_open' => '<table class="table table-striped table-hover">');
$this->table->set_template($style);
echo $this->table->generate($this->model_pakyaw->get_filtered_data($this->session->userdata('branch_name'), $this->input->post('date_from'), $this->input->post('date_to')));
}
型號:
public function get_filtered_data($branch_name, $date_from, $date_to){
$this->output->enable_profiler(TRUE);
$str2="select bio_id as 'bio_id', cast(attendance as date) as 'Log Date', min(attendance) as 'time_in', max(attendance) as 'time_out', timediff(max(attendance), min(attendance)) as 'difference'
FROM delwater_downydb.pakyaw_attendance
WHERE attendance > '".$date_from."'
GROUP BY bio_id, cast(attendance as date)
ORDER BY bio_id, cast(attendance as date) desc;";
$query=$this->db->query($str2);
return $query->result_array();
}
當我點擊btn_view_records時,它不會過濾結果。我查了一下,發現date_from沒有被傳遞。 SQL語法越來越''值,這就是爲什麼它沒有正確過濾。你能告訴我我做錯了什麼嗎?謝謝。
該代碼看起來沒有錯。你可以顯示'var_dump($ _ POST)'? – weirdo
我該如何實現?對不起,基本上是新的PHP .. – Ibanez1408
當我這樣做「print_r($ _ POST);死();」這只是這個.....「Array()」 – Ibanez1408