OverLoading方法Var無法解析。

Question

我得到的錯誤是「答案無法解決」。在頁面下方的1/4處。在網上看了看，仍然沒有看到它應該是什麼。使用while循環會更容易嗎？完全跳過循環？

import java.util.Scanner; 
public class RPSS{ 
//Main method 
    public static void main(String[ ] argc) 
    { 


    Scanner tnt = new Scanner(System.in); 
    String computerHand; // string variable for computer choice 
    String userHand; // string variable for user choice 
// do loop begining 
    do 
    { 
     computerHand = computerHand(); 
     userHand = userHand(); 
     String winner = getWinner(computerHand, userHand); 
     System.out.println(winner); 
     System.out.print("User picks" + userHand); 
     System.out.println("Computer picks " + computerHand); 
     System.out.println("play again?"); 
     String answer = tnt.next(); 


    //Condition for the do-while loop HERE IS THE ERROR LOCATION 
    }while (!answer.Equals("No") && (!answer.Equals("no"))); //condition for while loop 
    String answer = tnt.next(); 
    } 

    public static String userHand(){ //method for users choice in the game 

    //prints message to user giving them choices 
    System.out.println("Lets play rock paper scissors"); 
    System.out.println("1. Rock "); 
    System.out.println("2. Paper "); 
    System.out.println("3. Scissors "); 
    int userChoice; // user choice variable in this method 
    Scanner tnt = new Scanner(System.in); // creates instance of scanner class 
    userChoice = tnt.nextInt(); //reads user input 
    return getChoice(userChoice); //returns user choice to master choice 
    } 

    public static String computerHand() //method for computer generated choice 
    { 

    int computernum = (int)(Math.random() * ((3) + 1)); 
    return getChoice(computernum); 
    } 

    public static String getChoice(int num) //method recieving both computer hand and user hand 
    { 
// if statements to place the correct choice 
    String choice = ""; 
    if (num == 1){ 
     choice = "rock"; 
    } 
    else if(num == 2){ 
     choice = "paper"; 
    } 
    else if(num == 3){ 
     choice = "scissors"; 
    } 
    return choice; 
    } 
    // Method determing the winner 
    public static String getWinner(String computerChoice, String userChoice) 
    { 
    computerChoice = computerHand(); //places computerChoice variable in computerhand 
    userChoice = userHand(); //does same for user choice 
    String winner=""; 


    System.out.println(" the comp chose" + computerChoice); 

    if (userChoice.equals("Rock") && computerChoice.equals("Paper")){ 
     System.out.println("The computer"); } 

    else if (userChoice.equals("Paper") && computerChoice.equals("Scissors")){ 
     System.out.println(" The computer wins"); 
    } 

    else if (userChoice.equals("Scissors") && computerChoice.equals("Rock")){ 
     System.out.println(" The computer wins "); 
    } 
    else if (userChoice.equals("Rock") && computerChoice.equals("Paper")){ 
     System.out.println(" The computer wins "); 

    } 

    if (userChoice.equals(computerChoice)) 
    { 
     System.out.println(" There is no winner"); 
     } 
    return winner; 
    } 

} 

Answer 1

使用tnt.next()它返回下一個字符串。沒有這樣的東西，如nextString()。

另外，在getwinner方法的末尾添加return winner;。

Answer 2

您在do的大括號內標明answer，然後嘗試在大括號外使用它。一旦你離開大括號，變量就超出了範圍。