FosUserBundle我的自定義用戶實體未實現\ ArrayAccess接口

Question

我已經做了以下FormType以修改用戶個人資料：

namespace AppUserBundle\Form\Type; 

use Symfony\Component\Form\AbstractType; 
use Symfony\Component\Form\FormBuilderInterface; 
use Symfony\Component\Form\DataTransformerInterface; 
use Symfony\Component\Form\Extension\Core\Type\TextareaType; 

class UserProfileFormType extends AbstractType 
{ 
    public function buildForm(FormBuilderInterface $builder, array $options) 
    { 
     //$builder->addViewTransformer($this->purifierTransformer); 
     $builder->add('name'); 
     $builder->add('surname'); 
     $builder->add('description',TextareaType::class); 
    } 

// public function getParent() 
// { 
//  return 'FOS\UserBundle\Form\Type\ProfileFormType'; 
// } 

    public function getBlockPrefix() 
    { 
     return 'app_user_registration'; 
    } 

    // For Symfony 2.x 
    public function getName() 
    { 
     return $this->getBlockPrefix(); 
    } 
} 

而且我已經把它作爲一個這樣的服務：

app_user.user_profile_form: 
    class: AppUserBundle\Form\Type 
    tags: 
     - { name: form.type, alias: app_user_registration } 

而在config.yml以下CONFIGS：

fos_user: 
    ... 
    profile: 
    form: 
     type: AppUserBundle\Form\Type\UserProfileFormType 

正如我看到的documentation我可以完全覆蓋由只是不重寫getParent()方法的形式。由於單證說：

If you don't want to reuse the fields added in FOSUserBundle by default, you can omit the getParent method and configure all fields yourself.

，但我得到了以下錯誤：

Cannot read index "name" from object of type "AppUserBundle\Entity\User" because it doesn't implement \ArrayAccess.

請記住，在AppUserBundle\Entity\User具有下面的代碼：

namespace AppUserBundle\Entity; 

use FOS\UserBundle\Model\User as BaseUser; 
use Doctrine\ORM\Mapping as ORM; 
use Symfony\Component\Validator\Constraints as Assert; 

/** 
* @ORM\Entity 
* @ORM\Table(name="fos_user") 
*/ 
class User extends BaseUser 
{ 
    /** 
    * @ORM\Id 
    * @ORM\Column(type="integer") 
    * @ORM\GeneratedValue(strategy="AUTO") 
    */ 
    protected $id; 

    /** 
    * @ORM\Column(name="user_image", type="string", length=255, nullable=true) 
    */ 
    private $userImage; 

    /** 
    * @ORM\Column(name="name", type="string", length=255, nullable=true) 
    * @Assert\NotBlank(message="Please enter your name.", groups={"Registration", "Profile"}) 
    * @Assert\Length(
    *  min=3, 
    *  max=255, 
    *  minMessage="The name is too short.", 
    *  maxMessage="The name is too long.", 
    *  groups={"Registration", "Profile"} 
    *) 
    */ 
    private $name; 

    /** 
    * @ORM\Column(name="surname", type="string", length=255, nullable=true) 
    * @Assert\NotBlank(message="Please enter your name.", groups={"Registration", "Profile"}) 
    * @Assert\Length(
    *  min=3, 
    *  max=255, 
    *  minMessage="The surname is too short.", 
    *  maxMessage="The surname is too long.", 
    *  groups={"Registration", "Profile"} 
    *) 
    */ 
    private $surname; 

    /** 
    * @ORM\Column(name="description", type="string", length=1024, nullable=true) 
    */ 
    private $description; 

    public function __construct() 
    { 
     parent::__construct(); 
     // your own logic 
    } 

    public function setUserImage($imagepath) 
    { 
     $this->userImage=$imagepath; 
    } 

    public function functiongetUserImage() 
    { 
     return $this->userImage; 
    } 

    public function setName($name) 
    { 
     $this->name=strip_tags($name); 
    } 

    public function getName() 
    { 
     return $this->name; 
    } 

    public function setSurname($surname) 
    { 
     $this->surname=strip_tags($surname); 
    } 

    public function getSurname() 
    { 
     return $this->surname; 
    } 

    public function setDescription($description) 
    { 
     $this->description=$description; 
    } 

    public function getDescription() 
    { 
     return $this->description; 
    } 

我將原汁原味的任何幫助爲了解決這個謎團。

Answer 1

很老，但我也被困在這方面，我希望能幫助別人。您可以通過添加以下功能

$resolver->setDefaults(array(
     'data_class' => 'YourBundle\Entity\User', 
    )); 

告訴Symfony的您正在使用您的自定義登記表與您的用戶類