java.lang.outofmemoryerror位圖大小在位圖上超過vm預算

Question

在我的應用程序中，我顯示的圖像來自廚房和圖像選擇我想將圖像上傳到Web服務器。要將圖像上傳到服務器，我使用以下代碼，但我得到錯誤在 bitmapImage = BitmapFactory.decodeFile（path，opt）;

private void uploadImage(String selectedImagePath) { 
     String str = null; 
     byte[] data = null; 
     String Responce= null; 
     Bitmap bitmap2 = null; 
     try { 
      File file=new File(selectedImagePath); 
      //FileInputStream fileInputStream = new FileInputStream(new File(imagePath2)); 
      FileInputStream fileInputStream=new FileInputStream(selectedImagePath); 
      Log.i("Image path 2",""+selectedImagePath+"\n"+fileInputStream); 
      name=file.getName(); 
      name=name.replace(".jpg",""); 
      name=name.concat(sDate).concat(".jpg"); 
      Log.e("debug",""+name); 

      //else 
      //{ 
      BitmapFactory.Options options = new BitmapFactory.Options(); 
      options.inTempStorage = new byte[16*1024]; 

      //bitmapImage = BitmapFactory.decodeFile(path,opt); 

      bitmap2=BitmapFactory.decodeFileDescriptor(fd, outPadding, opts) 
      Log.i("Bitmap",""+bitmap.toString()); 
      BitmapFactory.decodeStream(fileInputStream); 
      ByteArrayOutputStream baos = new ByteArrayOutputStream(); 
      bitmap2.compress(Bitmap.CompressFormat.PNG, 100, baos); 
      data = baos.toByteArray(); 
      str=Base64.encodeBytes(data); 
      //} 

      //String image=str.concat(sDate); 
      ArrayList<NameValuePair> nameValuePairs = new 
      ArrayList<NameValuePair>(); 
      nameValuePairs.add(new BasicNameValuePair("image",str)); 
      nameValuePairs.add(new BasicNameValuePair("imagename", name)); 
      Log.e("debug",""+nameValuePairs.toString()); 

      HttpClient client=new DefaultHttpClient(); 
      HttpPost post=new HttpPost("http://ufindfish.b4live.com/uploadTipImage.php"); 

      post.setEntity(new UrlEncodedFormEntity(nameValuePairs)); 

      HttpResponse httpResponse=client.execute(post); 
      HttpEntity entity=httpResponse.getEntity(); 
      InputStream inputStream=entity.getContent(); 

      StringBuffer builder=new StringBuffer(); 
      int ch; 
      while((ch = inputStream.read()) != -1) 
      { 
       builder.append((char)ch); 
      } 
      String s=builder.toString(); 
      Log.i("Response",""+s); 



     } catch (FileNotFoundException e) { 
      // TODO Auto-generated catch block 
      e.printStackTrace(); 
     } catch (UnsupportedEncodingException e) { 
      // TODO Auto-generated catch block 
      e.printStackTrace(); 
     } catch (ClientProtocolException e) { 
      // TODO Auto-generated catch block 
      e.printStackTrace(); 
     } catch (IllegalStateException e) { 
      // TODO Auto-generated catch block 
      e.printStackTrace(); 
     } catch (IOException e) { 
      // TODO Auto-generated catch block 
      e.printStackTrace(); 
     } 
     if(bitmap2!=null) 
     { 
      bitmap2.recycle(); 
     } 

Answer 1

錯誤是由於圖像的大小，我使用此代碼來減少圖像的當從庫中選擇的大小。

public Bitmap setImageToImageView(String filePath) 
    { 
    // Decode image size 
    BitmapFactory.Options o = new BitmapFactory.Options(); 
    o.inJustDecodeBounds = true; 
    BitmapFactory.decodeFile(filePath, o); 

    // The new size we want to scale to 
    final int REQUIRED_SIZE = 1024; 

    // Find the correct scale value. It should be the power of 2. 
    int width_tmp = o.outWidth, height_tmp = o.outHeight; 
    int scale = 1; 
    while (true) 
    { 
    if (width_tmp < REQUIRED_SIZE && height_tmp < REQUIRED_SIZE) 
    break; 
    width_tmp /= 2; 
    height_tmp /= 2; 
    scale *= 2; 
    } 

    // Decode with inSampleSize 
    BitmapFactory.Options o2 = new BitmapFactory.Options(); 
    o2.inSampleSize = scale; 
    Bitmap bitmap = BitmapFactory.decodeFile(filePath, o2); 
    return bitmap; 

    } 

我希望這可以幫助你。

Answer 2

你必須打破對樣品加載圖像時，已經有一個問題，一個很好的答案吧，看看這個頁面，這可能會幫助你。

Strange out of memory issue while loading an image to a Bitmap object