我的android應用程序首先顯示提示信息,當收到消息時,以及從特定號碼收到消息時,顯示另一個提醒。但它沒有顯示第二個祝酒。安卓應用程序在比較電話號碼後無法完成任務
這裏是我的代碼:
import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;
import android.os.Bundle;
import android.telephony.SmsManager;
import android.telephony.SmsMessage;
import android.util.Log;
import android.widget.Toast;
public class IncomingSms extends BroadcastReceiver {
// Get the object of SmsManager
final SmsManager sms = SmsManager.getDefault();
public void onReceive(Context context, Intent intent) {
// Retrieves a map of extended data from the intent.
final Bundle bundle = intent.getExtras();
try {
if (bundle != null) {
final Object[] pdusObj = (Object[]) bundle.get("pdus");
for (int i = 0; i < pdusObj.length; i++) {
SmsMessage currentMessage = SmsMessage.createFromPdu((byte[]) pdusObj[i]);
String phoneNumber = currentMessage.getDisplayOriginatingAddress();
String senderNum = phoneNumber;
String message = currentMessage.getDisplayMessageBody();
Log.i("SmsReceiver", "senderNum: "+ senderNum + "; message: " + message);
int duration = Toast.LENGTH_SHORT;
Toast toast = Toast.makeText(context, "senderNum: "+ senderNum + ", message: " + message, duration);
toast.show();
String serverNumber= "+919886096376";
if(senderNum == serverNumber)
{
Toast toast1 = Toast.makeText(context,"alert message received!!!!",Toast.LENGTH_LONG);
toast.show();
}
} // end for loop
} // bundle is null
} catch (Exception e) {
Log.e("SmsReceiver", "Exception smsReceiver" +e);
}
}
}
@Varshini,你試過這個解決方案嗎? – Kedarnath
我做了,它的工作原理!謝謝! –
@varshinijagannath好聽的。沒關係。你可以接受我的答案:),除了我的答案之外,請打勾綠色標記。 – Kedarnath