嗨,我想檢查iOS設備上的iPhone設備版本。如何在iOS中查看iPhone設備版本?
我的意思是,當前正在運行的設備是iPhone 4或iPhone 5
我需要檢查設備,是iPhone 5或沒有?
因爲我的應用程序需要知道iPhone 5的問題。
那麼我該怎麼辦?
嗨,我想檢查iOS設備上的iPhone設備版本。如何在iOS中查看iPhone設備版本?
我的意思是,當前正在運行的設備是iPhone 4或iPhone 5
我需要檢查設備,是iPhone 5或沒有?
因爲我的應用程序需要知道iPhone 5的問題。
那麼我該怎麼辦?
添加以下代碼:
if(UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone){
if ([[UIScreen mainScreen] respondsToSelector: @selector(scale)]) {
CGSize result = [[UIScreen mainScreen] bounds].size;
CGFloat scale = [UIScreen mainScreen].scale;
result = CGSizeMake(result.width * scale, result.height * scale);
if(result.height == 960) {
NSLog(@"iPhone 4 Resolution");
resolution_number = 1;
}
if(result.height == 1136) {
NSLog(@"iPhone 5 Resolution");
}
}
else{
NSLog(@"Standard Resolution");
}
}
添加此宏到您的代碼:
#define HEIGHT_IPHONE_5 568
#define IS_IPHONE ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone)
#define IS_IPHONE_5 ([[UIScreen mainScreen] bounds ].size.height == HEIGHT_IPHONE_5)
然後只檢查每當你需要..
if (IS_IPHONE_5) {
//Code for iPhone5
}else{
//Code for earlier version
}
我居然發現使用#define那是訣竅
#define IS_IPHONE_5 (fabs((double)[[UIScreen mainScreen] bounds].size.height - (double) 568) < DBL_EPSILON)
在此基礎上question您可以將您的使用 本該模型確定的答案:
NSString *deviceModel = [UIDevice currentDevice].model;
結果可以是值之一:iPod的觸摸,iPhone,iPad的,iPhone模擬器,iPad的模擬器
您正在使用可能會創建這樣的UIDevice.h
類類別來確定哪個版本的具體型號爲:
的UIDevice + Utilities.h
#import <UIKit/UIKit.h>
@interface UIDevice (Utilities)
- (CGFloat)deviceModelVersion;
@end
的UIDevice + Utilities.m
#import "UIDevice+Utilities.h"
#include <sys/types.h>
#include <sys/sysctl.h>
@implementation UIDevice (Utilities)
- (CGFloat)deviceModelVersion
{
size_t size;
sysctlbyname("hw.machine", NULL, &size, NULL, 0);
char *machine = malloc(size);
sysctlbyname("hw.machine", machine, &size, NULL, 0);
NSString *platform = [NSString stringWithUTF8String:machine];
free(machine);
if ([platform rangeOfString:@"iPhone"].location != NSNotFound)
{
return [[[platform stringByReplacingOccurrencesOfString:@"iPhone" withString:@""] stringByReplacingOccurrencesOfString:@"," withString:@"."] floatValue];
}
else if ([platform rangeOfString:@"iPad"].location != NSNotFound)
{
return [[[platform stringByReplacingOccurrencesOfString:@"iPad" withString:@""] stringByReplacingOccurrencesOfString:@"," withString:@"."] floatValue];
}
else if ([platform rangeOfString:@"iPod"].location != NSNotFound)
{
return [[[platform stringByReplacingOccurrencesOfString:@"iPod" withString:@""] stringByReplacingOccurrencesOfString:@"," withString:@"."] floatValue];
}
else if ([platform rangeOfString:@"i386"].location != NSNotFound || [platform rangeOfString:@"x86_64"].location != NSNotFound)
{
return -1.0; //Currently it is not possible (or maybe it is, but I do not know)
//which type of simulator device model version your app is running
//so I am returning -1.0 device model version for all simulators types
}
return 0.0;
}
@end
實施例如何調用函數deviceModelVersion
:
CGFloat deviceModelVersion = [UIDevice currentDevice].deviceModelVersion;
可能的結果可以1.0,1.1,...,2.0,2.1,.. 3.0,3.1,...,4.0,4.1,...,5.0,5.1,...
要確定它是否是iPhone 5,你應該有
deviceModel : "iPhone"
和
deviceModelVersion : >=5.0 and < 6.0
#define IS_IPAD (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad)
#define IS_IPHONE (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
#define IS_IPHONE_4 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 480.0f)
#define IS_IPHONE_5 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 568.0f)
#define IS_IPHONE_6 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 667.0f)
#define IS_IPHONE_6PLUS (IS_IPHONE && [[UIScreen mainScreen] nativeScale] == 3.0f)
#define IS_IPHONE_6_PLUS (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 736.0f)
#define IS_RETINA ([[UIScreen mainScreen] scale] == 2.0f)
偉大的答案。這使得檢查範圍非常簡單,或者具有比可以用SYSTEM_VERSION_GREATER_THAN(..)完成的邏輯更類似的邏輯。愛它! – Marchy