按位置獲取日期（即1月的第三個星期三）？

Question

我可以在第三個星期三用strtotime（「星期三+星期」）還是需要像這樣的複雜代碼：http://www.danielkassner.com/2010/05/22/get-date-by-position-ie-third-wednesday-of-january？

Answer 1

試試這個： -

/** 
* int nth_day_of_month(int $nbr, str $day, int $mon, int $year) 
* $nbr = nth weekday to find 
* $day = full name of weekday, e.g. "Saturday" 
* $mon = month 1 - 12 
* $year = year 1970, 2007, etc. 
* returns UNIX time 
*/ 
function nth_day_of_month($nbr, $day, $mon, $year) 
{ 
    $date = mktime(0, 0, 0, $mon, 0, $year); 
    if($date == 0) 
    { 
     user_error(__FUNCTION__."(): Invalid month or year", E_USER_WARNING); 
     return(FALSE); 
    } 
    $day = ucfirst(strtolower($day)); 
    if(!in_array($day, array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 
     'Thursday', 'Friday', 'Saturday'))) 
    { 
     user_error(__FUNCTION__."(): Invalid day", E_USER_WARNING); 
     return(FALSE); 
    } 
    for($week = 1; $week <= $nbr; $week++) 
    { 
     $date = strtotime("next $day", $date); 
    } 
    return($date); 
} 


$d = nth_day_of_month($week_no,$curr_week_day, $fmonth, $fyear); 

echo date('d-m-Y',$d)."<br />"; 

Answer 2

此發現當月的第3個星期三。如果其用戶依賴，則更改$month的值。

編輯1：http://codepad.org/8OzgMQsA

編輯2：http://codepad.org/3Tn6Ypu2