JSON數組上的foreach循環

希望這是有道理...

進出口尋找從一個JSON數組中提取數據。

在下面的數組中，我想循環遍歷Response> data> bucket> Equippable> 1> items> 0>節點的節點選項卡，查看它是否處於活動狀態，以及它是否處於活動狀態。

問題是「節點」部分可以是兩種不同長度，本實施例中有12倍的結果，但下一個我的只有8等

對於固定的結果，我將利用本

foreach ($json['Response']['data']['buckets']['Equippable']['1']['items']['0']['nodes'] as $Talentnode) { 
$nodeActive[] = $Talentnode['0']['isActivated']; 
$nodeState[] = $Talentnode['0']['state']; 
}

如何將我做foreach循環時，我不知道會有多少結果？

[Response] => Array 

     [data] => Array 

       [buckets] => Array 

         [Invisible] => Array 
         [Item] => Array 
         [Equippable] => Array 

           [0] => Array 
           [1] => Array 

             [items] => Array 

               [0] => Array 

                 [itemHash] => 320170738 
                 [bindStatus] => 0 
                 [isEquipped] => 1 
                 [itemInstanceId] => 6917529121839082505 
                 [itemLevel] => 50 
                 [stackSize] => 1 
                 [qualityLevel] => 100 
                 [stats] => Array 
                 [primaryStat] => Array 
                 [canEquip] => 1 
                 [equipRequiredLevel] => 40 
                 [unlockFlagHashRequiredToEquip] => 2166136261 
                 [cannotEquipReason] => 0 
                 [damageType] => 1 
                 [damageTypeHash] => 3373582085 
                 [damageTypeNodeIndex] => 5 
                 [damageTypeStepIndex] => 0 
                 [progression] => Array 
                 [talentGridHash] => 2047220462 
                 [nodes] => Array 

                   [0] => Array 

                     [isActivated] => 1 
                     [stepIndex] => 0 
                     [state] => 10 
                     [hidden] => 
                     [nodeHash] => 0 

                   [1] => Array 

                     [isActivated] => 
                     [stepIndex] => 0 
                     [state] => 9 
                     [hidden] => 
                     [nodeHash] => 1 

                   [2] => Array 

                     [isActivated] => 1 
                     [stepIndex] => 0 
                     [state] => 10 
                     [hidden] => 
                     [nodeHash] => 2 

                   [3] => Array 

                     [isActivated] => 1 
                     [stepIndex] => 0 
                     [state] => 10 
                     [hidden] => 
                     [nodeHash] => 3 

                   [4] => Array 

                     [isActivated] => 
                     [stepIndex] => 0 
                     [state] => 9 
                     [hidden] => 
                     [nodeHash] => 4 

                   [5] => Array 

                     [isActivated] => 1 
                     [stepIndex] => 0 
                     [state] => 10 
                     [hidden] => 
                     [nodeHash] => 5 

                   [6] => Array 

                     [isActivated] => 1 
                     [stepIndex] => 0 
                     [state] => 0 
                     [hidden] => 
                     [nodeHash] => 6 

                   [7] => Array 

                     [isActivated] => 1 
                     [stepIndex] => 0 
                     [state] => 13 
                     [hidden] => 1 
                     [nodeHash] => 7 

                   [8] => Array 

                     [isActivated] => 
                     [stepIndex] => 0 
                     [state] => 9 
                     [hidden] => 
                     [nodeHash] => 8 

                   [9] => Array 

                     [isActivated] => 1 
                     [stepIndex] => 0 
                     [state] => 10 
                     [hidden] => 
                     [nodeHash] => 9 

                   [10] => Array 

                     [isActivated] => 
                     [stepIndex] => 0 
                     [state] => 9 
                     [hidden] => 
                     [nodeHash] => 10 

                   [11] => Array 

                     [isActivated] => 
                     [stepIndex] => 0 
                     [state] => 9 
                     [hidden] => 
                     [nodeHash] => 11 

                 [useCustomDyes] => 1 
                 [artRegions] => Array 
                 [isEquipment] => 1 
                 [isGridComplete] => 1 
                 [perks] => Array 
                 [location] => 1 
                 [transferStatus] => 1 
                 [locked] => 1 
                 [lockable] => 1 
                 [objectives] => Array 
                 [state] => 1

來源

2017-05-29 Ashley

你的代碼工作正常的'node'數組中的元素的任何量。爲什麼你認爲那裏不會有更多或更少的價值......？ – Enstage

你的循環很好，它應該遍歷所有的節點，但是有很多節點。

BTW：你應該打破它變成一個變量來使你的代碼在你的眼睛較不吃力：

$nodes = $json['Response']['data']['buckets']['Equippable']['1']['items']['0']['nodes']; 

foreach($nodes as $talentNode) { 
    // Perform operations on each nodes... 

    if($talentNode['isActivated']) 
      $nodesActive[] = $talentNode; 

    $nodeState[] = $talentNode['state']; 
} 

$nodesActive; // Array of the nodes active 
$nodeState; // Array with the state of each node

來源

2017-05-29 23:29:35 FrenchMajesty

感謝您使用您的更新版本的代碼，我如何找到哪些節點[isActivated] => 1且[state] => 10 – Ashley

@Ashley我已更新我的代碼示例，以顯示您將如何執行 – FrenchMajesty

JSON數組上的foreach循環

回答

相關問題