用bash中的列條件刪除CSV文件中的行

我有一個很大的CSV文件（5Go）。標題是：用bash中的列條件刪除CSV文件中的行

run number,export,downerQ,coefUpQuality,chooseMode,demandF,nbPLots,standarDevPop,nbCitys,whatWord,priceMaxWineF,marketColor,[step],giniIndexReserve,giniIndexPatch,meanQualityTotal,meanQualityMountain,meanQualityPlain,DiffExtCentral,nbcentralPlots,meanPatchByNetwork,sum_q_viti_moutain,sum_q_viti_plaine 
"3","false","0.5","0.01","false","7000","10","2","10","0","70","false","0","0","0.07083333333333335","0","0","0","0","0","0","48","0" 
"4","false","0.5","0.01","false","7000","10","2","10","0","70","false","0","0","0.04285714285714286","0","0","0","0","0","0","42","0" 
"2","false","0.5","0.01","false","7000","10","2","10","0","70","false","0","0","0.05348837209302328","0","0","0","0","0","0","43","0"

我想保留字段[步驟]（第十三字段）中只包含「500」的行。

我試圖SQLite中導入該CSV ...但刪除崩潰...
R還崩潰（甚至從data.table FREAD）

人是否有一個解決方案工具如sed,awk或其他命令？

來源

2015-01-20 delaye

查看[csvfix]（https://code.google.com/p/csvfix/）。它當然可以做到。在shell中，第一步可能是'grep -E'^ run number |，「500」，''來選擇標題行和包含500的地方的行;然後你可以用'awk'將它縮小到第13列中的500。或者你可以在awk中完成整個工作：'awk -F，'NR == 1 || $ 13 ==「\」500 \「」{print}「'（未經測試，您可能需要將'OFS'設置爲''''，但可能不需要）。 – 2015-01-20 20:44:28

AWK似乎要走的路：

awk -F, 'NR == 1 || $13 == "\"500\""' filename

哪裏NR == 1是保護第一線（頭），之後，它只是線，13號場"500"。

來源

2015-01-20 20:44:31 Wintermute

坦克你wintermute和喬納森......別忘了'-F，'爲'--field-separator' – delaye 2015-01-20 21:25:49

用bash中的列條件刪除CSV文件中的行

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