2015-09-09 134 views
3

我想做一個ajax點擊加載div功能。但點擊功能不起作用。我在這裏做錯了什麼?任何人都可以在這方面幫助我?jquery ajax點擊功能不會工作

DEMO從的jsfiddle

var response = '<div class="icon_b"> 
       <div class="clickficon"></div> 
        <div class="emicon-menu MaterialTabs"> 
         <ul> 
          <li class="tab active"><a href="#starks-panel1"> Starks</a></li> 
          <li class="tab"> <a href="#lannisters-panel1"> Lannisters</a></li> 
          <li class="tab"> <a href="#targaryens-panel1"> Targaryens</a><span></span></li> 
         </ul> 
         <div class="panels"> 
          <div id="starks-panel1" class="panel pactive"> a </div> 
          <div id="lannisters-panel1" class="panel"> b </div> 
          <div id="targaryens-panel1" class="panel"> c </div> 
         </div> 
        </div> 
       </div>'; 

$(document).ready(function() { 

    function showProfileTooltip(e, id) { 
     //send id & get info from get_profile.php 
     $.ajax({ 
      url: '/echo/html/', 
      data: { 
       html: response, 
       delay: 0 
      }, 
      method: 'post', 
      success: function (returnHtml) { 
       e.find('.user-container').html(returnHtml).promise().done(function() { 
        $('.emoticon').addClass('loaded'); 
       }); 
      } 
     }); 
    } 

    function hideProfileTooltip() { 
     $('.the-container').removeClass('loaded'); 
    } 
    $('body').on('change', '.emoticon', function(e) { 
     var id = $(this).find('.emoticon_click').attr('data-id'); 
     showProfileTooltip($(this), id); 
    }, function() { 
     hideProfileTooltip(); 
    }); 

}); 
+0

哪裏是單擊事件? – Zl3n

+0

它應該點擊不改變? – guradio

+0

@ Zl3n點擊事件是在ajax代碼中,請查看演示代碼:'var id = $(this).find('.emoticon_click')。attr('data-id');' – innovation

回答

2

回調函數無效在那裏,

//on load,click is more prefer than change 
$('body').on('click', '.emoticon', function(e) { 
    var id = $(this).find('.emoticon_click').attr('data-id'); 
    showProfileTooltip($(this), id); 
}); 
//don't call like this 
//, function() { 
// hideProfileTooltip(); 
// }); 
+0

但div不會關閉 – innovation