搜索文件夾並獲取文件內容

Question

我正在嘗試搜索文件夾並檢索文件夾內的文件（獲取內容）我可以使用以下代碼搜索文件夾但我不能從那裏通過我看不到內容檢索裏面的文件。裏面的文件將是txt文件，我希望能夠打開並看到。 如何才能實現我想要的？謝謝。

<?php 
$dirname = "C:\windows";//Directory to search in. *Must have a trailing slash* 
$findme = $_POST["search"]; 

$dir = opendir($dirname); 

while(false != ($file = readdir($dir))){//Loop for every item in the directory. 
if(($file != ".") and ($file != "..") and ($file != ".DS_Store") and ($file != 
"search.php"))//Exclude these files from the search 
{ 
$pos = stripos($file, $findme); 
if ($pos !== false){ 
$thereisafile = true;//Tell the script something was found. 
echo'<a href="' . $dirname . $file . '">' . $file . '</a><br>'; 
}else{ 

} 
} 
} 
if (!isset($thereisafile)){ 
echo "Nothing was found.";//Tell the user nothing was found. 
echo '<img src="yourimagehere.jpg"/>';//Display an image, when nothing was found. 
} 
?> 

Answer 1

以下代碼使用遞歸函數來搜索目錄。我希望它能解決你的問題。

function scandir_r($dir){ 
$files = array_diff(scandir($dir), array(".", "..")); 
$arr = array(); 
    foreach($files as $file){ 
    $arr[] = $dir.DIRECTORY_SEPARATOR.$file; 
     if(is_dir($dir.DIRECTORY_SEPARATOR.$file)){ 
     $arr = array_merge($arr, scandir_r($dir.DIRECTORY_SEPARATOR.$file)); 
     } 
    } 
return($arr); 
} 

$dirname = "C:\windows"; 
$findme = "/".preg_quote($_POST["search"], "/")."/"; 
$files = preg_grep($findme, scandir_r($dirname)); 
if(sizeof($files)){ 
    foreach($files as $file){ 
    $_file = $dirname.DIRECTORY_SEPARATOR.$file; 
    echo "<a href=\"$_file\">$file</a><br/>"; 
    } 
} 
else{ 
echo "Nothing was found."; 
echo "<img src=\"yourimagehere.jpg\"/>"; 
} 

Answer 2

新代碼

<?php 
$dirname = "C:\\Windows\\";//Directory to search in. *Must have a trailing slash* 
$findme = 'maxlink'; //$_POST["search"]; 

$files = scandir($dirname); 


foreach ($files AS $file) 
{ 
    if ($file == '.' or $file == '..' or $file == '.DS_Store' or $file == 'search.php') continue; 

    if (stripos($file, $findme) !== false) 
    { 
     $found = true; 
     echo 'FOUND FILE <a href="' . $dirname . $file . '">' . $file . '</a><hr>'; 
     echo 'OPENING IT:<br>'; 
     echo file_get_contents($dirname . $file); 
     echo '<hr>'; 
    } 
    else 
    { 
     echo 'not found: <a href="' . $dirname . $file . '">' . $file . '</a><br>'; 
    } 
} 

if (!isset($found)) 
{ 
    echo "Nothing was found.";//Tell the user nothing was found. 
    echo '<img src="yourimagehere.jpg"/>';//Display an image, when nothing was found. 
}