MySQL和正則表達式對INT

Question

此查詢應該返回4行，但隨着62983.任何理由ID返回1？

SELECT * 
    FROM sims_user_role_maps surm 
    JOIN sims_role sr ON surm.role_id = sr.id 
    WHERE 
     surm.user_id = 118730 
     AND sr.organization_id REGEXP 62978|62981|62982|62983 

SP呼叫

call schools_remove_for_user('f155ec0e-b9ce-11e1-a1fa-001cc4565d26', '62966|62969|62983') 

SP

CREATE PROCEDURE `schools_remove_for_user`(
    user_id NVARCHAR(255), 
    school_ids LONGTEXT 
) 
BEGIN 

DECLARE sims_user_id INT DEFAULT NULL; 

SELECT u.sims_id 
INTO sims_user_id 
FROM user u 
WHERE u.id = user_id; 

SET SQL_SAFE_UPDATES = 0; 

DELETE FROM sims_user_role_maps 
WHERE 
     user_id = sims_user_id 
    AND role_id IN (
       SELECT role_id 
       FROM(
        SELECT surm.role_id 
        FROM sims_user_role_maps surm 
        JOIN sims_role sr ON surm.role_id = sr.id 
        WHERE 
          surm.user_id = sims_user_id 
         AND sr.organization_id REGEXP school_ids) 
       A); 

END 

Answer 1

的原因是DELETE語句的USER_ID。我添加了表格名稱作爲前綴。

DELETE FROM sims_user_role_maps 
WHERE 
     sims_user_role_maps.user_id = sims_user_id 
    AND sims_user_role_maps.role_id IN (

Answer 2

你沒有把引號內的正則表達式，所以|作品bitwise OR。

正確的語法是AND sr.organization_id REGEXP '62978|62981|62982|62983'。你也可以考慮sr.organization_id IN (x, y, z)，如果你只是想匹配特定的整數，哪一個更好。