兩個日期字段之間的時差

Question

我有一個字符串格式的日期字段名稱「dts」。我想根據他們的時差（以小時計）找出所有記錄。運行事件時間應該大於或等於吃事件。

輸出應該是：

Answer 1

轉換時間戳來秒鐘，然後減，除結果通過3600拿到小時，用例+計數的範圍內來算，像這：

select count(case when diff_hrs >24 then 1 end) as more_24, 
     count(case when diff_hrs <=24 then 1 end) as less_than_24, 
     ... 
     count(case when diff_hrs >=2 and diff_hrs <=3 then 1 end) as hrs_2_to_3, 
     ... 
from 
(
select 
abs(unix_timestamp(dts) - unix_timestamp(dts-eat)))/60/60 as diff_hrs 
from table 
)s;