'145,153,8,1.35659494835128,155,C,H,H,H,H,H,H,H,H,H,H,H,H,H,C,X,X,X,1.000,0.000,0.000,0.286,0.429,0.000,0.286,0.000,0.286,0.571,0.000,0.143,0.000,0.143,0.000,0.143,0.429,0.286,0,2,0,0,3,1,0,1,3,3,1,0,1,1,0,X,X,X,1,3,0,0,3,1,0,1,3,3,1,0,3,3,0,X,X,X,3,1,3,3,0,3,4,3,0,0,3,4,2,1,4,X,X,X,0.265,0.213,0.523,0.155,0.265,0.052,0.374,0.155,0.290,0.232,0.097,0.381,0.000,0.187,0.174,0.077,0.348,0.213,0.143,0.143,0.000,0.000,0.000,0.143,0.000,0.000,0.000,0.143,0.143,0.000,0.000,0.000,0.143,0.000,0.143,0.000,0.000,0.000,E,E,E,E,E,4,4,3,4,3,3,3,3,3,1,0,1,2,0,3,0.077,0.052,0.039,0.045,0.013,0.065,0.052,0.065,0.026,0.026,0.065,0.058,0.006,0.071,0.058,0.071,0.052,0.019,0.039,0.103,0,0,0,2,-4,-1,2,-2,-3,-3,-3,3,-3,-4,0,2,2,-5,-3,-3,-2,-6,-6,-5,-6,-5,-5,-5,-6,-2,-4,-5,-1,-3,8,-3,-4,-7,-6,-1,0,-2,-1,2,-4,1,4,-3,-1,-3,0,1,0,-1,-3,0,-2,-4,-2,-3,1,-1,0,3,-4,1,2,-2,-1,-3,-4,2,-3,-4,-3,2,0,-5,-3,-2,-3,-5,-5,-5,-4,-4,-5,-6,-5,5,3,-5,4,0,-4,-4,-3,-4,-3,1,1,1,-2,0,-3,-1,5,-3,-2,-1,-2,1,-2,-4,-3,-1,-1,-2,-3,1,1,0,0,1,-4,1,2,-1,-1,-4,-3,4,-3,-5,2,0,0,-5,-4,-3,2,-1,-1,5,-4,0,2,-3,0,-4,-5,0,-4,-4,-2,-1,-1,1,-2,-3,-4,-6,-6,-6,-4,-6,-6,-7,-6,7,1,-6,-1,-3,-6,-5,-4,-6,-4,2,-4,-6,-6,-6,-4,-6,-6,-7,-6,7,1,-6,-1,-3,-6,-5,-4,-6,-4,2,0,-1,-2,1,-5,2,5,-4,-2,-2,-1,2,-3,-5,-2,-2,-1,-5,-3,0,2,1,-1,-1,-4,1,2,-3,-3,-4,-4,5,-3,-5,-2,0,-1,-5,-4,-3,2,-4,-5,-5,-2,-2,-1,-5,-4,-1,5,-4,1,-1,-5,-3,-2,-1,0,-1,-4,-5,-6,-7,-3,-5,-6,-7,-6,2,6,-5,-1,-2,-6,-5,-4,-5,-4,1,-3,3,2,-1,-5,2,4,-3,-2,-5,-4,4,-3,-5,-3,-2,-2,-5,-4,-4,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,-3,-5,-5,-6,-3,-5,-5,-6,-5,5,2,-5,0,5,-5,-4,-3,-3,-2,3,-4,-5,-5,-6,-6,-4,-5,-6,5,-5,-2,-5,-4,2,-5,-4,-5,-1,9,-5,-3,-3,0,7,-6,1,3,-2,-1,-6,-6,-2,-3,-6,-3,0,-2,-6,-5,-5,-5,-6,-6,-6,-4,-5,-6,-6,-2,2,1,-6,-2,8,-6,-5,-3,-2,2,-2,-1,-1,0,-2,-3,1,2,-3,-1,-3,-4,2,-2,-4,2,2,3,-5,-3,-2,0\n'
我的列表中的每個單獨項目都包含類似上面的內容,但具有不同的編號。我想保留前兩個值,但是擺脫其他一切。所以對於上面的例子。最終結果將是145,153
。我的目錄大小是145,我想在我的名單要做到這一點每個元素從陣列中的每個單獨元素中刪除一些東西
1
A
回答
5
lst = ['145,153,8,1.3565949', '1,2,3,4,5,6', '9,8,7,6,5,4']
[','.join(elem.split(',', 2)[:2]) for elem in lst]
回報
['145,153', '1,2', '9,8']
+2
不知道分裂的第二個參數!很好:) – 2013-04-05 10:48:13
+0
爲什麼我不能馬上接受它,我不想等2分鐘 – miik 2013-04-05 10:57:58
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好來舉個例子,但請縮短下一次。下面的問題幾乎消失了。 – eumiro 2013-04-05 10:50:17
感謝您的意見,會做:) – miik 2013-04-05 10:57:10