如果用戶在某個特定的持續時間內處於非活動狀態，使用codeigniter如何自動註銷

Question

如果用戶在某個特定的持續時間內處於非活動狀態，則應該自動註銷。那麼我怎樣才能使用codeigniter來做到這一點？ 或 如何在用戶登錄後檢查用戶是否活動？

Answer 1

// Add the following into your HEAD section 
var timer = 0; 
function set_interval() { 
    // the interval 'timer' is set as soon as the page loads 
    timer = setInterval("auto_logout()", 10000); 
    // the figure '10000' above indicates how many milliseconds the timer be set to. 
    // Eg: to set it to 5 mins, calculate 5min = 5x60 = 300 sec = 300,000 millisec. 
    // So set it to 300000 
} 

function reset_interval() { 
    //resets the timer. The timer is reset on each of the below events: 
    // 1. mousemove 2. mouseclick 3. key press 4. scroliing 
    //first step: clear the existing timer 

    if (timer != 0) { 
    clearInterval(timer); 
    timer = 0; 
    // second step: implement the timer again 
    timer = setInterval("auto_logout()", 10000); 
    // completed the reset of the timer 
    } 
} 

function auto_logout() { 
    // this function will redirect the user to the logout script 
    window.location = "your_logout_script.php"; 
} 

// Add the following attributes into your BODY tag 
onload="set_interval()" 
onmousemove="reset_interval()" 
onclick="reset_interval()" 
onkeypress="reset_interval()" 
onscroll="reset_interval()" 

Answer 2

您可以保存您的用戶登錄的session或cookie

實例時間：$this->session->set_userdata('time', time()); 並使用javascriptjQuery函數（試驗$.getJSON('time.php', function (data) {alert(data.serverTime);});）或其他任何檢查當前時間。然後，在需要時將用戶註銷。

但是，下次請放置代碼或其他可顯示您的工作的其他內容。

Answer 3

<?php 
    $minutes=3;//Set logout time in minutes  
    if (!isset($_SESSION['time'])) { 
     $_SESSION['time'] = time(); 
    } else if (time() – $_SESSION['time'] > $minutes*60) { 
     session_destroy(); 
     header(‘location:login.php’);//redirect user to a login page or any page to which we want to redirect. 
    } 
?> 

...它最初是從 skillrow.com/log-out-user-if-user-is-inactive-for-certain-time-php/（現爲404）拍攝。