用COUNT（*）返回Mysql結果

我試圖從mysql返回一個計數。我的代碼如下用COUNT（*）返回Mysql結果

$number_of_options_sql = tep_db_query("SELECT COUNT(*) FROM 
(select sum(options_id) as total from products_attributes 
where products_id='".$products_id."' group by options_id) as total"); 
$number_of_options_result = tep_db_fetch_array($number_of_options_sql);

當我運行在phpMyAdmin此查詢，它顯示了COUNT(*)在表頭的結果。我得到正確的結果，查詢適用於我，我無法將其打印在屏幕上。

我試圖返回值通過以下方式和屏幕上沒有一個打印任何東西：後COUNT(*)

$number_of_options_sql = tep_db_query("SELECT COUNT(*) AS field_name FROM (select sum(options_id) as total from products_attributes where products_id='".$products_id."' group by options_id) as total");

echo $number_of_options_result[COUNT(*)]; 
echo $number_of_options_result[total];

來源

2011-01-05 Ryan

缺少行情？ – Bobby 2011-01-05 15:58:18

您的查詢是將一個別名分配給表/查詢而不是列。使用下面這個：

$number_of_options_sql = tep_db_query("SELECT COUNT(*) as total FROM (select sum(options_id) as total from products_attributes where products_id='".$products_id."' group by options_id) a"); 
$number_of_options_result = tep_db_fetch_array($number_of_options_sql);

也像你想知道不同的ID選項的數量爲PRODUCT_ID，我將如下重新編寫查詢：

$number_of_options_sql = tep_db_query("SELECT COUNT(DISTINCT options_id) as total FROM products_attributes WHERE products_id='".$products_id."'");

來源

2011-01-05 15:59:31 Chandu

重寫查詢對我來說非常合適。謝謝！ – Ryan 2011-01-05 16:13:03

使用AS field_name要打印：

echo $number_of_options_result['field_name'];

（將「field_name」替換爲您的菜單的任何相關名稱CE）

來源

2011-01-05 15:58:58 RabidFire

只要編輯您的查詢

SELECT COUNT(*) as count FROM ....

那麼它將被保存，如「計數」，你可以打印在$ number_of_options_result [統計]辦法。

來源

2011-01-05 15:59:22 tsusanka

放於一個變量「總」

$number_of_options_sql = tep_db_query("SELECT COUNT(*) as total

然後它

echo $number_of_options_result['total'];

來源

2011-01-05 15:59:47 nerkn

用COUNT（*）返回Mysql結果

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