我想通過jQuery和AJAX將文本框的值(發票號)發送到PHP文件。從PHP文件中,我返回JSON編碼數據。我想在下面的文本框(總金額,餘額)和選擇框(支付模式,付款狀態)中顯示從數據庫中提取的值。通過jQuery和PHP加載JSON數據
我沒有得到我希望的輸出。我哪裏錯了?
HTML:
<form name="inv_payment" method="post" action="" style="margin:0px;width:400px;">
<fieldset>
<legend>Payment details</legend>
<label for=inv_num>Invoice Number</label>
<input id=inv_num name=inv_num type=number placeholder="12345" required autofocus >
<input type=button name="get_details" id="get_details" value="Get Details" >
<label for=tot_amt>Total Amount</label>
<input id=tot_amt name=tot_amt type=text placeholder="12345" disabled > <br/>
<label for=pay_up>Pay Up </label>
<input id=pay_up name=pay_up type=text placeholder="12345" required ><br/>
<label for=bal_amt>Balance Amount </label>
<input id=bal_amt name=bal_amt type=text placeholder="12345" disabled > <br/>
<label id="paymt_mode"><strong>Payment Mode</strong></label>
<select name="pay_mode" style="width: 130px">
<option selected="selected">Cash</option>
<option>Cheque</option>
</select><br/>
<label id="paymt_status"><strong>Payment Status</strong> </label>
<select name="pay_status" style="width: 130px">
<option selected="selected">Pending</option>
<option>Completed</option>
</select><br/>
<input type="submit" value="Payment" name="pay_btn">
</fieldset>
</form>
的jQuery:
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$('#get_details').click(function() {
//To pass the invoice number and fetch related details
$.getJSON("get_invpay_details.php", {id: $('#inv_num').val()}, function(data){
$('#tot_amt').val(data['Total_Amount']);
$('#bal_amt').val(data['Balance_Amount']);
$('#pay_mode').val(data['Payment_Type']);
$('#pay_status').val(data['Payment_Status']);
});
});
</script>
PHP:
<?php
include('includes/dbfunctions.php');
include('includes/db.php');
if(isset($_GET['id']))
{
$tmp = $_GET['id'];
$sql = mysql_query("select Total_Amount,Balance_Amount,Payment_Type,Payment_Status from invoice where InvoiceNum='$tmp'");
if(mysql_num_rows($sql))
{
$data = mysql_fetch_array($sql);
echo json_encode($data);
}
}
?>
如果它不是你希望的輸出,你到底是什麼?另外,考慮轉移到mysqli或PDO,你的查詢看起來很奇怪! – adeneo 2013-04-29 06:38:08
告訴我們你的json響應...檢查你的控制檯.. – bipen 2013-04-29 06:39:50
你可以顯示你的'json_encode($ data)'內容.. – Ranjith 2013-04-29 06:41:20