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這仍然沒有運行,但希望它會給一些更多的信息 限制文件清單:我有這段代碼:從XML文件失敗
#import modules
import os, sys, datetime, time
# sys.setdefaultencoding is cancelled by site.py
reload(sys) # to re-enable sys.setdefaultencoding()
sys.setdefaultencoding('utf-8')
try:
import xml.etree.cElementTree as ET
except ImportError:
import xml.etree.ElementTree as ET
now = datetime.datetime.now()
today = now.strftime("%m/%d/%Y")
processed = 0
#here if sync_list.xml doesn't exist, I ask for some user input i want to save between sessions
#then I save that info to sync_list.xml, along with the element to store files already synced
root = ET.Element("root")
synced = ET.SubElement(root, "synced")
synced.set("name", "Already Synced")
sfile = ET.SubElement(synced, "sfile")
sfile.set("date", today)
sfile.text = "firstsync"
tree = ET.ElementTree(root)
tree.write("sync_list.xml")
#If sync_list.xml already exists, then I grab the info
tree = ET.parse("sync_list.xml")
root = tree.getroot()
#I pull in all the info I need to work with and:
for elem in root.findall('sfile'):
synced = elem.text
dcheck = 0
for elem in root.findall('synced/sfile'):
fdate = elem.attrib.get('date')
if fdate == today:
dcheck += 1
synced = [elt.text for elt in root.findall('synced/sfile')]
#if sync_list.xml exists get the list of (UUIDs) $entries that have already been synced, and exclude them from the current query. If no UUID's exist in sync_list.xml, ignore
synclimit = 10 - dcheck
print "Already synced today: " + str(dcheck)
print "Today's synclimit: " + str(synclimit)
if synclimit == 0:
print "Sorry, you've reached your limit for file syncing today. The limit is reset each night at 12:00 a.m."
sys.exit()
synclimit = int(raw_input("How many files do you want to sync today? You have a max amount of " + str(synclimit) + " left today: "))
for filename in os.listdir(filepath):
if processed >= synclimit:
print "You've successfully synced " + str(synclimit) + " files."
sys.exit()
else:
if filename.endswith('.txt') and filename not in synced:
filename = os.path.join(filepath, filename)
#process the files. This is where I'm getting variable dofilename
#The processing works correctly. It's just going over the same files that have already been synced
tree = ET.parse('sync_list.xml')
synced = tree.find('synced')
sfile = ET.SubElement(synced, "sfile", date=today)
sfile.text = dofilename
tree.write('sync_list.xml', encoding='utf-8', xml_declaration=True)
processed += 1
print 'Synced ' + dofilename + '....>'
print 'done!'
和它是什麼意思做的是檢查sync_list文件名,而不是處理這些文件。
預期輸出: 如果我有一個目錄:
,我跑在第1天的劇本爲5的synclimit,我希望將XML輸出看起來像:
<sfile date="11/26/2012">file1.txt</sfile>
<sfile date="11/26/2012">file2.txt</sfile>
<sfile date="11/26/2012">file3.txt</sfile>
<sfile date="11/26/2012">file4.txt</sfile>
<sfile date="11/26/2012">file5.txt</sfile>
這個按預期工作,但如果我在第二天以10的同步限制運行它,我會得到:
<sfile date="11/26/2012">file1.txt</sfile>
<sfile date="11/26/2012">file2.txt</sfile>
<sfile date="11/26/2012">file3.txt</sfile>
<sfile date="11/26/2012">file4.txt</sfile>
<sfile date="11/26/2012">file5.txt</sfile>
<sfile date="11/27/2012">file1.txt</sfile>
<sfile date="11/27/2012">file2.txt</sfile>
<sfile date="11/27/2012">file3.txt</sfile>
<sfile date="11/27/2012">file4.txt</sfile>
<sfile date="11/27/2012">file5.txt</sfile>
<sfile date="11/27/2012">file6.txt</sfile>
<sfile date="11/27/2012">file7.txt</sfile>
我所期待的,會是這樣,無論什麼synclimit設置爲,該腳本將跳過已經被處理過這些文件,而是給我這樣的輸出:
<sfile date="11/26/2012">file1.txt</sfile>
<sfile date="11/26/2012">file2.txt</sfile>
<sfile date="11/26/2012">file3.txt</sfile>
<sfile date="11/26/2012">file4.txt</sfile>
<sfile date="11/26/2012">file5.txt</sfile>
<sfile date="11/27/2012">file6.txt</sfile>
<sfile date="11/27/2012">file7.txt</sfile>
感恩對於任何指導,關於我誤入歧途的地方。
你的代碼沒有什麼明顯的錯誤,但是它沒有足夠的能夠運行它。你可以發佈一個運行的例子(包括輸入數據和預期輸出)並顯示問題。這將使我們更容易測試它。 – aquavitae
製作一個簡單的文件(例如'done_list.csv'),並在當天存儲一個處理文件列表;然後在程序開始時使用此文件在第二天(將來日期)進行驗證;(例如:您可以驗證已處理的日期爲'26'的任何文件此次不會處理(在'27 'th)..並在每次處理後更新該文件中的信息..。簡單.. – namit
我以爲這就是我在用'if filename.endswith('。txt')和文件名不在同步:我正在檢查sync_list.xml以確保條目尚未同步,如果是,我希望它會跳過它。 – sosukeinu