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請記住,我完全是OOP概念的新手,我一直在嘗試從mysql數據庫檢索數據並回顯結果。是那樣簡單,但我有這麼及彼不同的錯誤是應該返回結果無法回顯數組結果「未定義的變量:行」
function fetchUserByEmail($email=NULL)
{
if($email!=NULL) {
$column = "email";
$data = $email;
}
global $mysqli,$db_table_prefix;
$stmt = $mysqli->prepare("SELECT
id,
user_name,
display_name,
password,
email,
activation_token,
last_activation_request,
lost_password_request,
active,
title,
sign_up_stamp,
last_sign_in_stamp
FROM ".$db_table_prefix."users
WHERE
$column = ?
LIMIT 1");
$stmt->bind_param("s", $data);
$stmt->execute();
$stmt->bind_result($id, $user, $display, $password, $email, $token, $activationRequest, $passwordRequest, $active, $title, $signUp, $signIn);
while ($stmt->fetch()){
$row = array('id' => $id, 'user_name' => $user, 'display_name' => $display, 'password' => $password, 'email' => $email, 'activation_token' => $token, 'last_activation_request' => $activationRequest, 'lost_password_request' => $passwordRequest, 'active' => $active, 'title' => $title, 'sign_up_stamp' => $signUp, 'last_sign_in_stamp' => $signIn);
}
$stmt->close();
return ($row);
}
什麼,我需要知道的是完全相同的功能,我要去如何調用結果在html標籤
這裏是我的嘗試:
$email = mysql_real_escape_string($_POST['email']);
fetchUserByEmail($email);
?><ul>
<div style="background-color:#EEEEEE" class="content">
<li>
<h2><?php echo $row['id'];?></h2>
我得到通知:未定義的變量:ERROR
'$行= fetchUserByEmail($電子郵件);' – vee