2011-01-07 56 views
3

請幫我理解正確的連接語法。concat in php codeigniter

我有一個名爲表庫存其中有:

trans_id  
trans_items items -> item_id   
trans_user employees -> person_id   
trans_date     
trans_comment     
trans_inventory  

正如你可以在上面看到,trans_items是在項目表的外鍵,並且trans_user是員工表的外鍵和員工ID是國外關鍵人桌。

現在我想要做的是在HTML中顯示庫存表,但不是顯示員工ID,我希望顯示員工姓名。


編輯.......................................... ...... ,所以我能夠以僅顯示與此代碼僱員的名字:

$this->db->select('inventory.*, items.name ,people.last_name'); 
$this->db->from('inventory'); 
$this->db->join('items', 'inventory.trans_items = items.item_id' , 'left'); 
$this->db->join('people', 'inventory.trans_user = people.person_id' , 'left'); 
$this->db->where('deleted', 0); 
$this->db->order_by('trans_date desc'); 

與模型代碼:

foreach($report_data as $row) 
     { 
      $tabular_data[] = array($row['name'], $row['last_name'],$row['trans_date'], $row['trans_inventory'], $row['trans_comment']); 
     } 

,但我需要它是第一姓名,所以我做了這些:

$this->db->select('inventory.*, items.name ,CONCAT(people.first_name, " ",people.last_name) as employee'); 
$this->db->from('inventory'); 
$this->db->join('items', 'inventory.trans_items = items.item_id' , 'left'); 
$this->db->join('people', 'inventory.trans_user = people.person_id' , 'left'); 
$this->db->where('deleted', 0); 
$this->db->order_by('trans_date desc'); 

與模型代碼:

foreach($report_data as $row) 
     { 
      $tabular_data[] = array($row['name'], $row['employee'],$row['trans_date'], $row['trans_inventory'], $row['trans_comment']); 
     } 

將錯誤,如果我會用concat函數。請幫忙。

+0

@AntonioCS:在回答你的標誌,則`mysql`標籤被添加到標題爲搜索引擎優化的目的。請參閱[關鍵字的順序是否與頁面標題有關?](http://webmasters.stackexchange.com/questions/6556/does-the-order-of-keywords-matter-in-a-page-標題)和[爲什麼第一個標籤有時在標籤的某些問題?](http://meta.stackexchange.com/questions/71922/why-is-the-first-tag-sometimes-in-the- -的幾家,問題標題標籤)。 – <span class="text-secondary"> <small> <span>2011-01-07 12:21:02</span> </small> </span> </p> </div> </div> </div> </div> </div> </article> </div> <div class="answer-title"> <span class="text-logo margin-top-sm">A</span> <h2 class="title h4">回答</h2> </div> <div class="item-description text-md markdown-body margin-bottom-40 voidso"> <article class="board-top-1 padding-top-10"> <div class="post-col vote-info"> <span class="count">21<i class="fa fa-thumbs-up"></i></span> </div> <div class="post-offset"> <div class="answer fmt"> <p>你的選擇必須是這樣的(在$第二個參數這個 - > DB->選擇( '您的選擇部分',FALSE)):從笨手動</p> <pre><code class="prettyprint-override">$this->db->select('inventory.*, items.name ,CONCAT(people.first_name, " ",people.last_name) as employee', FALSE); $this->db->from('inventory'); $this->db->join('items', 'inventory.trans_items = items.item_id' , 'left'); $this->db->join('people', 'inventory.trans_user = people.person_id' , 'left'); $this->db->where('deleted', 0); $this->db->order_by('trans_date desc'); </code></pre> <p>報價:</p> <blockquote> <p>如果將其設置爲FALSE,CodeIgniter 將不會嘗試使用反引號保護您的字段或 表名。如果您需要複合選擇 聲明,這是 有用。</p> </blockquote> </div> <div class="post-info"> <div class="post-meta row"> <p class="text-secondary col-lg-6"> <span class="source"> <a rel="noopener" target="_blank" href="https://stackoverflow.com/q/4623968">來源</a> </span> </p> <p class="text-secondary col-lg-6"> <span class="float-right date"> <span>2011-01-07 09:09:15</span> <a rel="noopener" target="_blank" href="https://stackoverflow.com/users/565339/">Diablo</a></span> </p> <p class="col-12"></p> <p class="col-12"></p></div> </div> <!-- comments --> <div class="comments"> <div itemprop="comment" class="post-comment"> <div class="row"> <div class="col-lg-1"><span class="text-secondary">+0</span></div> <div class="col-lg-11"> <p class="commenttext">非常快。謝謝。也謝謝 – <span class="text-secondary"> <small> <span>2011-01-07 09:22:19</span> </small> </span> </p> </div> </div> </div> </div> </div> </article> <div> <script async src="https://pagead2.googlesyndication.com/pagead/js/adsbygoogle.js"></script> <ins class="adsbygoogle" style="display:block" data-ad-client="ca-pub-6208739752673518" data-ad-slot="1038284119" data-ad-format="auto" data-full-width-responsive="true"></ins> <script> (adsbygoogle = window.adsbygoogle || []).push({}); </script> </div> <article class="board-top-1 padding-top-10"> <div class="post-col vote-info"> <span class="count">0<i class="fa fa-thumbs-up"></i></span> </div> <div class="post-offset"> <div class="answer fmt"> <pre><code class="prettyprint-override">$query=$this->db->select("id, CONCAT(nombre,".' '.",apellido_paterno) as nombre", false)-> from("empleado")-> where('empleado', $filtro)-> order_by("nombre")-> get(); </code></pre> <p>只會增加假選擇</p> </div> <div class="post-info"> <div class="post-meta row"> <p class="text-secondary col-lg-6"> <span class="source"> <a rel="noopener" target="_blank" href="https://stackoverflow.com/q/22884921">來源</a> </span> </p> <p class="text-secondary col-lg-6"> <span class="float-right date"> <span>2014-04-05 18:24:13</span> <a rel="noopener" target="_blank" href="https://stackoverflow.com/users/3934078/">user3934078</a></span> </p> <p class="col-12"></p> <p class="col-12"></p></div> </div> </div> </article> </div> <div class="clearfix"> </div> <div class="relative-box"> <div class="relative">相關問題</div> <ul class="relative_list"> <li> 1. <a href="http://hk.uwenku.com/question/p-caftksau-rb.html" target="_blank" title="concat in FSharp.Core.String vs Concat in System.String"> concat in FSharp.Core.String vs Concat in System.String </a> </li> <li> 2. <a 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