轉換$ note1 = mysql_result（$ result，0，「note_content」）;到mysqli的等效

Question

我有工作得很好以下舊的PHP代碼：

<?php 
$query = "SELECT * FROM notes WHERE note_name='Test Note'"; 
$result = mysql_query($query); 

$note1 = mysql_result($result, 0, "note_content"); 
$note2 = mysql_result($result, 1, "note_content"); 

echo "<p>$note1</p> 
<p>$note2</p>" 
?> 

我想將它轉化成mysqli的。我做了以下將它轉換，但它不工作：

<?php 
$query = "SELECT * FROM notes WHERE note_name='Test Note'"; 
$result = mysqli_query($connect, $query); 

// THIS IS WHERE I AM UNSURE WHAT TO DO??? HERE'S WHAT I TRIED 
$row = mysqli_fetch_array($result, MYSQLI_ASSOC); 

$note1 = $row["note_content"][0]; 
$note2 = $row["note_content"][1]; 

echo "<p>$note1</p> 
<p>$note2</p>" 
?> 

我在做什麼錯？如果沒有，你要取分開的每一行

$all_rows = mysqli_fetch_all($result, MYSQLI_ASSOC); 
$note1 = $all_rows[0]["note_content"]; 
$note2 = $all_rows[1]["note_content"]; 

：

Answer 1

如果您已經安裝了mysqlnd驅動程序，你可以做到這一點

$row = mysqli_fetch_assoc($result); 
$note1 = $row["note_content"]; 
$row = mysqli_fetch_assoc($result); 
$note2 = $row["note_content"];