我有一個只包含一個hasmap類型屬性的對象。用hasmap將對象轉換爲XML使用Jackson
public class Application {
private Map<String,Object> map2;
public Map<String, Object> getMap2() {
return Collections.unmodifiableMap(map2);
}
public void setMap2(Map<String, Object> map2) {
this.map2 = map2;
}
}
我嘗試生成與傑克遜的XML:
Map<String,Object> map = new HashMap<String, Object>();
map.put("key1", "value1");
map.put("key2", "value2");
XmlMapper xmlMapper = new XmlMapper();
xmlMapper.configure(ToXmlGenerator.Feature.WRITE_XML_DECLARATION, true);
System.out.println(xmlMapper.writeValueAsString(app));
結果是:
<?xml version='1.0' encoding='UTF-8'?>
<Application>
<Map2>
<key1>value1</key1>
<key2>value2</key2>
</Map2>
</Application>
但我想只有有:
<?xml version='1.0' encoding='UTF-8'?>
<Application>
<key1>value1</key1>
<key2>value2</key2>
</Application>
我怎樣才能移除Map2元素?
我已經嘗試過這解。如果我使用HashMap而不是整個對象,則獲得:<?xml version ='1.0'encoding ='UTF-8'?> value1 value2 。那麼我怎麼才能將HashMap重命名爲Application? –
gduh
是的,它實際上獲得了hasmap類。 – noshusan
那麼,我創建了一個擴展HashMap類的新類Application。現在沒關係。但解決方案並非真正的「乾淨」! – gduh