我只寫了這樣的事情,上週,作爲一個事實問題。我沒有太多時間,所以沒有優化或漂亮。
雖然我使用了XDocument。
static XDocument GetXDocument(List<GoogleProduct> googleProducts)
{
XNamespace gns = "http://base.google.com/ns/1.0";
XDocument document = new XDocument(
new XElement("rss",
new XAttribute("version", "2.0"),
new XAttribute(XNamespace.Xmlns + "g", gns),
new XElement("channel",
new XElement("title", "X Company Feed"),
new XElement("description", "X Description"),
new XElement("link", "http://www.somecompany.com/"),
from googleProduct in googleProducts
select new XElement("item",
new XElement("title", googleProduct.Title),
new XElement(gns + "brand", googleProduct.ProductRecommendedAttributes.Brand),
new XElement(gns + "manufacturer", googleProduct.ProductRecommendedAttributes.Manufacturer),
new XElement(gns + "condition", googleProduct.Condition),
new XElement("description", googleProduct.Description),
new XElement(gns + "id", googleProduct.ID),
from img in googleProduct.ProductRecommendedAttributes.ImageLinks
select new XElement(gns + "image_link", img),
new XElement("link", googleProduct.Link),
new XElement(gns + "price", googleProduct.Price.ToString("0.00")),
new XElement(gns + "product_type", googleProduct.ProductRecommendedAttributes.ProductType),
from pmt in googleProduct.ProductOptionalAttributes.PaymentAccepteds
select new XElement(gns + "payment_accepted", pmt)))));
//
return document;
}
(FYI:GoogleProduct只是我使用的臨時映射類)
它會生成沿着這些線路
<?xml version="1.0" encoding="utf-8"?>
<rss version="2.0" xmlns:g="http://base.google.com/ns/1.0">
<channel>
<title>Blah Data Feed</title>
<description>Stuff from Blah</description>
<link>http://www.blah.com/shopping</link>
<item>
<title>Blah</title>
<g:brand>Blah</g:brand>
<g:manufacturer>Blah</g:manufacturer>
<g:condition>New</g:condition>
<description>blah blah</description>
<g:id>268</g:id>
<g:image_link>http://www.blah.com/shopping/images/PRODUCT/medium/268.jpg</g:image_link>
<link>http://www.blah.com/</link>
<g:price>1747.00</g:price>
<g:product_type>Blah Blah</g:product_type>
<g:payment_accepted>Cash</g:payment_accepted>
<g:payment_accepted>Check</g:payment_accepted>
<g:payment_accepted>Visa</g:payment_accepted>
<g:payment_accepted>Mastercard</g:payment_accepted>
</item>
<item>
<title>Blah</title>
<g:brand>Blah</g:brand>
<g:manufacturer>Blah</g:manufacturer>
<g:condition>New</g:condition>
<description>blah blah</description>
<g:id>269</g:id>
<g:image_link>http://www.blah.com/shopping/images/PRODUCT/medium/269.jpg</g:image_link>
<link>http://www.blah.com/</link>
<g:price>1103.00</g:price>
<g:product_type>blah blah</g:product_type>
<g:payment_accepted>Cash</g:payment_accepted>
<g:payment_accepted>Check</g:payment_accepted>
<g:payment_accepted>Visa</g:payment_accepted>
<g:payment_accepted>Mastercard</g:payment_accepted>
</item>
</channel>
</rss>
感謝您的信息。我希望有可能使用SyndicationItem等,但我會嘗試你的方法。 – Peter 2010-03-30 20:44:40
通過一切手段,探索!就像我說的那樣,我受到了時間的壓力,而且我對Linq-to-XML很滿意,所以這對我來說是一條自然的道路。 – 2010-03-30 20:46:27
我一直在探索找到它,但似乎不可能使用SyndicateFeed將RSS名稱空間添加到RSS標籤:( – Peter 2010-03-30 21:00:09