無法更新SQLite數據庫中的整數字段

我想通過向SQLite數據庫中添加1來更新'整數'字段。因此，它是X = X+1無法更新SQLite數據庫中的整數字段

以下是我的代碼

public synchronized void updateStatistics(List<String> correctWords, 
      List<String> facedWords, int wordListNumber, boolean flag) { 
     // TODO Auto-generated method stub 
     String[] tableLastNames= {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"}; 

     String tableName = "WordList_"+tableLastNames[wordListNumber]; 


     if(flag) 
     { 
      //First update 'FacedWords' row 

      Toast.makeText(context, "Faced Words Length: "+facedWords.size(), Toast.LENGTH_LONG).show(); 
      Toast.makeText(context, "Correct Words Length: "+correctWords.size(), Toast.LENGTH_LONG).show(); 

      try 
      { 
       for(int i=0;i<facedWords.size();i++) 
       { 
        String query = "update "+ tableName+" set NumberOfTimesEnglishWordShowed=NumberOfTimesEnglishWordShowed+1 where EnglishWord = ' "+(facedWords.get(i)).trim()+"'"; 
        database.execSQL(query); 
       } 

       for(int i=0;i<correctWords.size();i++) 
       { 
        String query = "update "+ tableName+" set NumberOfTimesEnglishWordCorrected=NumberOfTimesEnglishWordCorrected+1 where EnglishWord = ' "+(facedWords.get(i)).trim()+"'"; 
        database.execSQL(query); 
       } 

       //Toast.makeText(context, "Updated Word: "+, duration) 
      } 
      catch(Exception e) 
      { 
       Toast.makeText(context, "Update error", Toast.LENGTH_LONG).show(); 
      } 

     } 



    }

我使用的SQLite數據庫瀏覽器中看到我的數據庫中的事情，我注意到上面的代碼無關更新！沒有錯誤！如果你需要，下面是所需的部分從表

String createDatabaseQuery = "create table WordList_A(" + 
        "ID integer primary key autoincrement," 
        +"NumberOfTimesEnglishWordShowed integer," 

        +"NumberOfTimesEnglishWordCorrected integer,");";

我使用的更新查詢類似於MS SQL更新查詢，所以我不知道這樣是否正在使用SQLite。爲什麼我的代碼沒有更新任何內容？

請幫

來源

2013-08-12 Yohan Weerasinghe

是全球領先的空間'」「+ （facedWords.get（i））。trim（）+「''是故意的嗎？這似乎是錯的... –

@Heuster：太棒了！就是這個！謝謝！由於您首先發現問題，因此我想將您的答案標記爲答案。請提供答案作爲答案 –

Tnx，但只是將其他答案標記爲已接受。這不是一場比賽:) –

我覺得你有額外的「空間」的where子句：

where EnglishWord = ' "+(facedWords.get(i)).trim()+"'"

所以將其替換爲：

where EnglishWord = '"+(facedWords.get(i)).trim()+"'"

來源

2013-08-12 07:19:08

你好，非常感謝你的回答。有用！我已經給了你一個+1 –

你的歡樂和ty，+1，祝你好運 –

無法更新SQLite數據庫中的整數字段

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