MySQL錯誤150（外鍵問題？）

Question

我想創建一系列具有多個外鍵關係的表。兩個表中的第一個有兩列主鍵，一次由我們指定，另一個由製造商指定。當嘗試第三個查詢時發生該錯誤。我不確定這裏出了什麼問題，所以任何幫助都會受到真誠的讚賞。

SQL

CREATE TABLE rugs (
    id INTEGER NOT NULL AUTO_INCREMENT, 
    manufacturer_id INTEGER NOT NULL, 
    name VARCHAR(255), 
    description TEXT, 
    PRIMARY KEY (id, manufacturer_id) 
); 

CREATE TABLE carpets (
    id INTEGER NOT NULL AUTO_INCREMENT, 
    manufacturer_id INTEGER NOT NULL, 
    name VARCHAR(255), 
    warranty TEXT, 
    description TEXT, 
    fiber_name VARCHAR(255), 
    brand_name VARCHAR(255), 
    texture_name VARCHAR(255), 
    PRIMARY KEY (id, manufacturer_id) 
); 

CREATE TABLE carpet_styles (
    id INTEGER NOT NULL AUTO_INCREMENT, 
    carpet_id INTEGER, 
    style_name VARCHAR(255), 
    PRIMARY KEY (id), 
    FOREIGN KEY (carpet_id) REFERENCES carpets (manufacturer_id) 
); 

CREATE TABLE carpet_colors (
    id INTEGER NOT NULL AUTO_INCREMENT, 
    carpet_id INTEGER, 
    color_name VARCHAR(255), 
    color_category VARCHAR(255), 
    PRIMARY KEY (id), 
    FOREIGN KEY (carpet_id) REFERENCES carpets (manufacturer_id) 
); 

CREATE TABLE carpet_custom_names (
    id INTEGER NOT NULL AUTO_INCREMENT, 
    carpet_id INTEGER, 
    custom_name VARCHAR(255), 
    PRIMARY KEY (id), 
    FOREIGN KEY (carpet_id) REFERENCES carpets (manufacturer_id) 
); 

CREATE TABLE rug_styles (
    id INTEGER NOT NULL AUTO_INCREMENT, 
    rug_id INTEGER, 
    style_name VARCHAR(255), 
    PRIMARY KEY (id), 
    FOREIGN KEY (rug_id) REFERENCES rugs (manufacturer_id) 
); 

CREATE TABLE rug_colors (
    id INTEGER NOT NULL AUTO_INCREMENT, 
    rug_id INTEGER, 
    color_name VARCHAR(255), 
    color_category VARCHAR(255), 
    PRIMARY KEY (id), 
    FOREIGN KEY (rug_id) REFERENCES rugs (manufacturer_id) 
); 

CREATE TABLE rug_shapes (
    id INTEGER NOT NULL AUTO_INCREMENT, 
    rug_id INTEGER, 
    shape_name VARCHAR(255), 
    shape_category VARCHAR(255), 
    PRIMARY KEY (id), 
    FOREIGN KEY (rug_id) REFERENCES rugs (manufacturer_id) 
); 

CREATE TABLE catalog_contents (
    id INTEGER NOT NULL AUTO_INCREMENT, 
    catalog_id INTEGER, 
    carpet_id INTEGER, 
    rug_id INTEGER, 
    PRIMARY KEY (id), 
    FOREIGN KEY (rug_id) REFERENCES rugs (id), 
    FOREIGN KEY (carpet_id) REFERENCES carpets (id), 
    FOREIGN KEY (catalog_id) REFERENCES catalogs (id) 
); 

Answer 1

這似乎是由於這樣的事實，雖然carpets.manufacturer_id是複合鍵的一部分，它有沒有自己的指數。您必須從複合PRIMARY KEY分開創建一個索引。這同樣適用於rugs.manufacturer_id

CREATE TABLE rugs (
    id INTEGER NOT NULL AUTO_INCREMENT, 
    manufacturer_id INTEGER NOT NULL, 
    name VARCHAR(255), 
    description TEXT, 
    /* manufacturer_id gets its own index */ 
    PRIMARY KEY (id, manufacturer_id), 
    INDEX idx_rugs_manufacturer_id (manufacturer_id) 
); 


CREATE TABLE carpets (
    id INTEGER NOT NULL AUTO_INCREMENT, 
    manufacturer_id INTEGER NOT NULL, 
    name VARCHAR(255), 
    warranty TEXT, 
    description TEXT, 
    fiber_name VARCHAR(255), 
    brand_name VARCHAR(255), 
    texture_name VARCHAR(255), 
    PRIMARY KEY (id, manufacturer_id), 
    /* manufacturer_id gets its own index */ 
    INDEX idx_manufacturer_id (manufacturer_id) 
);